Exhibit
>>> my_list = [[1,2], [3,4], [5,6]] >>> for i in range(len(my_list)): ... for j in range(len(my_list[i])): ... if my_list[i][j] % 2 == 0: ... my_list[i][j] = 0 >>> print(my_list)
This PCEP practice question tests your understanding of control flow, loops, lists and logic. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
>>> my_list = [[1,2], [3,4], [5,6]] >>> for i in range(len(my_list)): ... for j in range(len(my_list[i])): ... if my_list[i][j] % 2 == 0: ... my_list[i][j] = 0 >>> print(my_list)
Refer to the exhibit. What is the output of the code?
>>> my_list = [[1,2], [3,4], [5,6]] >>> for i in range(len(my_list)): ... for j in range(len(my_list[i])): ... if my_list[i][j] % 2 == 0: ... my_list[i][j] = 0 >>> print(my_list)
Answer choices
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
[[1, 0], [3, 0], [5, 0]]
The code iterates over the list `[[1,2],[3,4],[5,6]]` and for each inner list, it sets the element at index 1 to 0. This mutates each inner list in place, producing `[[1,0],[3,0],[5,0]]`. The original list is then printed, showing the modified nested list.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Common exam traps
Cisco often tests the distinction between modifying list elements in place versus creating new lists, and the trap here is that candidates mistakenly think the loop creates new sublists or that only the outer list is modified, leading them to choose the original or incorrectly altered output.
Detailed technical explanation
In Python, lists are mutable objects, so modifying an element inside a nested list (e.g., `sublist[1] = 0`) directly alters the original list structure. The `for` loop iterates over references to the inner lists, not copies, so changes persist after the loop. This behavior is fundamental to understanding how Python handles list mutation in-place versus creating new objects.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
A practitioner preparing for the PCEP exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
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FAQ
Control Flow, Loops, Lists and Logic — This question tests Control Flow, Loops, Lists and Logic — Read the scenario before looking for a memorised answer..
The correct answer is: [[1, 0], [3, 0], [5, 0]] — The code iterates over the list `[[1,2],[3,4],[5,6]]` and for each inner list, it sets the element at index 1 to 0. This mutates each inner list in place, producing `[[1,0],[3,0],[5,0]]`. The original list is then printed, showing the modified nested list.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Read the scenario before looking for a memorised answer.
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Last reviewed: Jul 4, 2026
This PCEP practice question is part of Courseiva's free Python Institute certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the PCEP exam.
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