PCEP Control Flow, Loops, Lists and Logic Practice Question

A programmer wants to create a list of even numbers from 0 to 10 inclusive. Which list comprehension is correct?

⚠ Common exam trap

Python Institute often tests the distinction between `range(0,11)` and `range(0,10)` to catch candidates who forget that the stop value is exclusive, and the use of truthy/falsy values in conditions (e.g., `if x%2` instead of `if x%2==0`) to confuse even vs. odd selection.

Answer choices

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Correct answer & explanation

✓

[x for x in range(0,11) if x%2==0]

It uses `range(0,11)` to generate numbers from 0 to 10 inclusive, and the condition `if x%2==0` selects only even numbers (where the remainder when divided by 2 is 0). This matches the requirement exactly.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

✓
[x for x in range(0,11) if x%2==0]
Why this is correct
The comprehension iterates over `range(0,11)`, whose stop value is exclusive, so it yields 0 through 10 inclusive as the stem requires. The filter `x%2==0` then retains only even values, producing `[0,2,4,6,8,10]` in a single expression without needing an explicit append loop.
✗
[x for x in range(0,10) if x%2==0]
Why it's wrong here
range(0,10) stops at 9, so 10 is excluded and the result is 0, 2, 4, 6, 8 rather than including 10. It is tempting because the modulo condition is correct and range's exclusive upper bound is easy to overlook; range(0,11) would include 10.
✗
[x for x in range(0,11) if x%2]
Why it's wrong here
Non-zero values are truthy, gives odd numbers.
✗
[x for x in range(0,11) if x%2==1]
Why it's wrong here
Gives odd numbers.

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PCEP Control Flow, Loops, Lists and Logic Practice Question

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