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Working with Arrays and CollectionshardMultiple ChoiceObjective-mapped

1Z0-829 Working with Arrays and Collections Practice Question

Which of the following correctly describes the behavior of the following code? List<String> list = new ArrayList<>(); list.add("A"); list.add("B");

for (String s : list) {
    if (s.equals("A")) {

list.remove(s);

}
}

System.out.println(list);

⚠ Common exam trap

A common mix-up: candidates think the for-each loop will safely remove the element and continue, or that the exception only occurs with multiple threads, but in fact any structural modification (add, remove, clear) to the underlying collection during single-threaded iteration triggers the fail-fast mechanism.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

ConcurrentModificationException is thrown

The code uses an enhanced for-each loop to iterate over an ArrayList while calling `list.remove(s)` when the element equals "A". This modifies the list structurally during iteration, which causes the iterator (used internally by the for-each loop) to detect the concurrent modification and throw a `ConcurrentModificationException` at runtime. The exception is thrown because the iterator's `modCount` check fails when the list is modified outside of the iterator's own `remove` method.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • ConcurrentModificationException is thrown

    Why this is correct

    Fail-fast behavior.

  • Compilation error

    Why it's wrong here

    Code compiles correctly.

  • [B]

    Why it's wrong here

    Exception thrown before completing iteration.

  • [A, B] unchanged

    Why it's wrong here

    Modification causes exception.

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Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

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