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Working with Arrays and CollectionseasyMultiple ChoiceObjective-mapped

1Z0-829 Working with Arrays and Collections Practice Question

Exhibit

Refer to the exhibit.

List<String> list = new ArrayList<>();
list.add("A");
list.add("B");
list.add("C");
list.add("A");
System.out.println(list.indexOf("A"));
System.out.println(list.lastIndexOf("A"));

What is the output of the following code?

List<Integer> list = List.of(0, 1, 2, 3); System.out.println(list.indexOf(0) + " " + list.lastIndexOf(3));

⚠ Common exam trap

Candidates might mistakenly think that lastIndexOf(3) returns 2 due to off-by-one error, or confuse with other list methods like get().

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

0 3

The list is [0, 1, 2, 3]. The indexOf(0) returns 0 because 0 is at index 0. The lastIndexOf(3) returns 3 because 3 is at index 3. The output is "0 3".

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • 0 2

    Why it's wrong here

    This would be the output if lastIndexOf(3) returned 2, which is incorrect because 3 is at index 3.

  • 0 3

    Why this is correct

    Correct: indexOf(0) returns 0 and lastIndexOf(3) returns 3.

  • 1 2

    Why it's wrong here

    This would require indexOf(0) to return 1 and lastIndexOf(3) to return 2, both incorrect.

  • 1 3

    Why it's wrong here

    This would require indexOf(0) to return 1, which is incorrect.

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