Working with Arrays and Collections →easyMultiple ChoiceObjective-mapped

1Z0-829 Working with Arrays and Collections Practice Question

Exhibit

Refer to the exhibit.
```java
import java.util.*;
public class Test {
    public static void main(String[] args) {
        Map<String, Integer> map = new HashMap<>();
        map.put("X", 10);
        map.put("Y", 20);
        map.put("Z", 30);
        System.out.println(map.get("Y"));
    }
}
```

What is the output?

⚠ Common exam trap

The trap is that candidates may expect the output to include the key (e.g., "Y=20") because they confuse the return value of get() with an entry's toString() representation. The get() method returns only the value (or null if absent), not a formatted key-value string.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

The code creates a HashMap and adds a mapping from key "Y" to value 20. When it retrieves the value for key "Y" using get(), it returns 20. The output is simply the integer 20, not the string "Y=20". Therefore, option C is correct.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

✗
Y=20
Why it's wrong here
The map's toString would show that, but not get method.
✗
null
Why it's wrong here
Key "Y" exists, so value is returned, not null.
✓
20
Why this is correct
The key "Y" maps to 20.
✗
Exception
Why it's wrong here
No exception; get returns the value or null if key absent.

Go deeper

1Z0-829 Working with Arrays and Collections Practice Question

Exhibit

Why each option matters

Option-by-option breakdown

Related to this question