Utilizing Java Object-Oriented Approach →hardMultiple ChoiceObjective-mapped

1Z0-829 Utilizing Java Object-Oriented Approach Practice Question

Exhibit

public class Outer {
    private int x = 10;
    class Inner {
        private int x = 20;
        void method() {
            int x = 30;
            System.out.println(x);
            System.out.println(this.x);
            System.out.println(Outer.this.x);
        }
    }
    public static void main(String[] args) {
        Outer.Inner inner = new Outer().new Inner();
        inner.method();
    }
}

Refer to the exhibit. What is the output?

⚠ Common exam trap

Watch out — candidates often confuse push() with add() (which adds to the tail) and assume the iteration order matches insertion order, rather than recognizing that push() places elements at the front for LIFO access.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

30 20 10

The code uses a Deque (ArrayDeque) and calls push() to add elements, which adds them to the front of the deque (LIFO order). The for-each loop iterates from the head (first) to the tail (last), so it prints 30, 20, 10. Option B is correct because push() behaves like a stack, and iteration follows the deque's head-to-tail order.

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1Z0-829 Utilizing Java Object-Oriented Approach Practice Question

Exhibit

Why each option matters

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