Question 504 of 513
1Z0-829 Method Overriding Practice Question
Exhibit
Refer to the exhibit.
public class Main {
public static void main(String[] args) {
System.out.println("Hello");
}
}
And the command:
$ javac Main.java
$ java Main
Output:
Hello
Now consider this class in another file:
public class Sub extends Main {
public static void main(String[] args) {
System.out.println("World");
}
}
Compiled and run:
$ java Sub
What is the output?Refer to the exhibit. Two Java classes are defined as shown. What is the output when the Sub class is executed?
⚠ Common exam trap
Oracle often tests whether candidates understand that an overridden method in a subclass does not automatically execute the superclass version unless explicitly called with super.method(), leading many to mistakenly think the superclass method runs first by default.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
World
The Sub class overrides the print() method from Super and does not call super.print(). Therefore, when Sub's print() is executed, it only prints "World" without printing "Hello". The output is simply "World".
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
HelloWorld
Why it's wrong here
Only Sub's main method runs, not both.
- ✓
World
Why this is correct
Sub's main method is executed, printing 'World'.
- ✗
Hello
Why it's wrong here
Sub's main method does not invoke Main's main; it prints 'World'.
- ✗
No output (compilation error)
Why it's wrong here
Both classes compile and run without error.
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Same concept, more angles
1 more way this is tested on 1Z0-829
These questions test the same concept from different angles. Work through them to make sure you can recognise it however the exam phrases it.
Variation 1. Refer to the exhibit. What is the result?
hard- A.Compilation fails
- ✓ B.Bark Playing
- C.Runtime exception
- D.Bark
Why B: The code compiles and runs without error. The object referenced by a1 is a Dog instance. The code first calls the bark() method, which prints 'Bark' (defined in Dog). Then it calls the play() method, which is not overridden in Dog, so it invokes the inherited play() method from Animal, printing 'Playing'. Therefore, the output is 'Bark' followed by 'Playing', which matches option B.
Last reviewed: Jun 30, 2026
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