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Working with Arrays and CollectionshardMultiple ChoiceObjective-mapped

1Z0-829 Working with Arrays and Collections Practice Question

Given: Map<String, Integer> map = new HashMap<>(); map.put("A", 1); map.put("B", 2); map.merge("A", 3, (v1, v2) -> v1 + v2); System.out.println(map.get("A")); What is the result?

⚠ Common exam trap

Many exam-takers confuse `merge` with `put` or `replace`, forgetting that the remapping function combines the old and new values rather than simply overwriting with the new value.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

4

(4) because the `merge` method on a Map associates the key "A" with the result of applying the remapping function `(v1, v2) -> v1 + v2` to the current value (1) and the given value (3), producing 1 + 3 = 4. If the key had been absent, the new value would be 3, but since it is present, the function is invoked and the result replaces the old value.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • 1

    Why it's wrong here

    Incorrect; merge updates the value.

  • 4

    Why this is correct

    Correct: 1+3=4.

  • 3

    Why it's wrong here

    Incorrect; it adds both values.

  • null

    Why it's wrong here

    Incorrect; key exists, so not null.

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