695-2168-4565-a967-300d847a5d54","difficulty":"medium","questionType":"multiple_choice","pbqConfig":null,"exhibitText":null,"options":[{"id":"baf99ef4-85e6-44a4-acf0-64a07dd6c40d","label":null,"text":"for (String s : list) { if (s.equals(\"x\")) list.remove(s); break; }","isCorrect":false},{"id":"7a02193d-947f-45e7-9e9b-e2ae19679a7d","label":null,"text":"for (int i = 0; i < list.size(); i++) { if (list.get(i).equals(\"x\")) list.remove(i); }","isCorrect":false},{"id":"d7aaf77e-a5ca-4161-ad6e-4198fd5e7da0","label":null,"text":"Iterator it = list.iterator(); while (it.hasNext()) { if (it.next().equals(\"x\")) it.remove(); }","isCorrect":true},{"id":"4864e052-afeb-4486-ba09-cf8ffbbe79ca","label":null,"text":"for (String s : list) { if (s.equals(\"x\")) list.remove(s); }","isCorrect":false}],"domainName":"Working with Arrays and Collections","domainSlug":"arrays-collections"},{"id":"cd41cbea-027a-469f-995c-2eb431495221","slug":"refer-to-the-exhibit-what-is-the-output-ex-0muc","questionText":"Refer to the exhibit. What is the output?","explanation":"The code groups names by the length of their string using `Collectors.groupingBy(String::length, Collectors.toList())`. The names \"Alice\" and \"David\" have length 5, \"Bob\" has length 3, and \"Charlie\" has length 7. The resulting map has keys 3, 5, and 7. Although `groupingBy` returns a `HashMap` without guaranteed order, the expected output in this context displays the keys in ascending numerical order: 3, 5, 7. Therefore, option C correctly shows the groups in that order with the corresponding names. Option B is incorrect because it lists the keys in non-ascending order (5, 3, 7), which does not match the typical output format.","domainId":"b5e6056f-afa9-4785-88a4-82ede285131f","difficulty":"hard","questionType":"multiple_choice","pbqConfig":null,"exhibitText":"List names = Arrays.asList(\"Alice\", \"Bob\", \"Charlie\", \"David\");\nMap> grouped = names.stream()\n .collect(Collectors.groupingBy(String::length));\nSystem.out.println(grouped);","options":[{"id":"f0cc6ada-8762-4e10-9bf0-f0b057517bae","label":null,"text":"{3=[Bob], 5=[Alice, David, Charlie]}","isCorrect":false},{"id":"f060b040-f6f7-4594-abf3-0ca757171446","label":null,"text":"{5=[Alice, David], 3=[Bob], 7=[Charlie]}","isCorrect":false},{"id":"03c352e1-8400-4f82-baf1-8cdf4fc7674d","label":null,"text":"{3=[Bob], 5=[Alice, David], 7=[Charlie]}","isCorrect":true},{"id":"e6899e00-7e25-45ed-9d4e-976daa0486e0","label":null,"text":"{3=[Bob], 5=[Alice], 7=[Charlie, David]}","isCorrect":false}],"domainName":"Working with Streams and Lambda Expressions","domainSlug":"streams-lambdas"},{"id":"44900d51-dfb7-4913-b084-34f7c7345c47","slug":"which-code-will-successfully-produce-an-optional-integer-th-1th46","questionText":"Which code will successfully produce an Optional that contains the maximum value from a list of integers?","explanation":"Option A is correct because it states that options B and D both produce Optional. Option B uses list.stream().collect(Collectors.maxBy(Integer::compareTo)), which returns an Optional containing the maximum element. Option D uses list.stream().max(Integer::compareTo), which also returns an Optional with the maximum element. Option C, list.stream().max() without arguments, fails to compile because the Stream.max() method requires a Comparator. Therefore, A is the correct choice.","domainId":"b5e6056f-afa9-4785-88a4-82ede285131f","difficulty":"easy","questionType":"multiple_choice","pbqConfig":null,"exhibitText":null,"options":[{"id":"f71b99e3-3aea-4c92-b413-55c0527a54e4","label":null,"text":"B and D both produce Optional.","isCorrect":true},{"id":"28d98414-f059-494e-a997-0945571aa153","label":null,"text":"list.stream().collect(Collectors.maxBy(Integer::compareTo))","isCorrect":false},{"id":"49c9e844-9310-46a6-a0cb-91e8fb3b98b1","label":null,"text":"list.stream().max()","isCorrect":false},{"id":"e61cbb21-396c-4157-a1ba-2ff8b9951d53","label":null,"text":"list.stream().max(Integer::compareTo)","isCorrect":fal