1Z0-829 Handling Exceptions Practice Question
Consider the following code snippet:
try { // some code
} catch (IOException e) {// handle
} catch (FileNotFoundException e) { // Line X// handle
}
What will be the result?
⚠ Common exam trap
It's easy for candidates to think the code compiles and the second catch simply never runs, but Java enforces this at compile time to prevent unreachable code, not just at runtime.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
Compilation fails at Line X with an error about an exception already caught.
In Java, when catching exceptions, the more specific exception subclass must be caught before the more general superclass. FileNotFoundException is a subclass of IOException, so catching IOException first makes the catch for FileNotFoundException unreachable, causing a compilation error at Line X.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
The code compiles and runs without issues.
Why it's wrong here
FileNotFoundException is a subclass of IOException, so the order causes unreachable code.
- ✗
The code compiles but throws a ClassCastException at runtime.
Why it's wrong here
No runtime exception related to catch ordering.
- ✗
The code compiles but the second catch never executes.
Why it's wrong here
Compilation fails, so it never runs.
- ✓
Compilation fails at Line X with an error about an exception already caught.
Why this is correct
Correct: FileNotFoundException is already caught by IOException.
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Written by Johnson Ajibi, MSc IT Security
Senior Network & Security Engineer · founder of Courseiva
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