Question 304 of 509
Working with Streams and Lambda ExpressionseasyMultiple ChoiceObjective-mapped

Quick Answer

The correct approach is `opt.stream().map(String::toUpperCase).forEach(System.out::println);` because it converts the `Optional` into a `Stream` using the `stream()` method, enabling a functional pipeline that naturally handles the presence or absence of a value. When the `Optional` is empty, the stream is empty, so `forEach` does nothing—avoiding explicit `ifPresent` checks while still allowing transformation via `map`. On the Oracle Certified Professional Java SE 17 Developer 1Z0-829 exam, this pattern tests your understanding of bridging `Optional` with the Stream API, a common scenario for chaining operations like filtering or flat-mapping. A frequent trap is using `ifPresent` with a lambda that manually creates a stream, which defeats the purpose of the concise, lazy-evaluation approach. Remember the mnemonic: **“Stream the Optional, map the value, forEach the output”**—this keeps your code declarative and exam-ready.

1Z0-829 Working with Streams and Lambda Expressions Practice Question

This 1Z0-829 practice question tests your understanding of working with streams and lambda expressions. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.

A method returns an Optional<String>. The developer wants to transform the value inside the Optional to uppercase and print it, but only if present. Which best-practice approach uses streams?

Clue words in this question

Noticing these words before you look at the options changes how you read each choice.

  • Clue: "best"

    Why it matters: Signals that multiple options may be partially correct. Choose the option that most directly solves the exact problem described, not the one that sounds most complete.

Question 1easymultiple choice
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Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

opt.stream().map(String::toUpperCase).forEach(System.out::println);

Option C is correct because it converts the Optional to a Stream using opt.stream(), then applies map(String::toUpperCase) to transform the value, and finally uses forEach(System.out::println) to print it only if present. This approach leverages the Stream API's lazy evaluation and functional pipeline, which is the best practice for integrating Optional with streams.

Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • opt.map(String::toUpperCase).ifPresent(System.out::println);

    Why it's wrong here

    This is also valid and uses Optional's map, but it is not a stream approach. The question specifically asks for streams.

  • opt.ifPresent(s -> System.out.println(s.toUpperCase()));

    Why it's wrong here

    This does not use streams; it's a valid approach but not stream-based.

  • opt.stream().map(String::toUpperCase).forEach(System.out::println);

    Why this is correct

    This converts Optional to a stream of one or zero elements, applies transformation, and prints. It is a stream-based best practice.

    Clue confirmation

    The clue word "best" in the question point toward this answer.

    Related concept

    Read the scenario before looking for a memorised answer.

  • Stream.of(opt).map(o -> o.get().toUpperCase()).forEach(System.out::println);

    Why it's wrong here

    This may throw NoSuchElementException if Optional is empty; also it wraps the Optional itself, not the content.

Common exam traps

Common exam trap: answer the scenario, not the keyword

The trap here is that candidates may overlook the 'uses streams' constraint and pick A or B, which are valid Optional operations but not stream-based, or pick D which misuses Stream.of to wrap the Optional instead of converting it.

Detailed technical explanation

How to think about this question

Under the hood, Optional.stream() (introduced in Java 9) returns a sequential Stream containing the value if present, or an empty Stream if not, enabling seamless integration with stream pipelines. This avoids manual null checks or get() calls, aligning with functional programming principles. In real-world scenarios, this is useful when chaining multiple Optional transformations within a larger stream operation, such as filtering or flatMapping.

KKey Concepts to Remember

  • Read the scenario before looking for a memorised answer.
  • Find the constraint that changes the correct option.
  • Eliminate answers that are true in general but not in this case.

TExam Day Tips

  • Watch for words such as best, first, most likely and least administrative effort.
  • Review why wrong options are wrong, not only why the correct option is correct.

Key takeaway

Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Real-world example

How this comes up in practice

A practitioner preparing for the 1Z0-829 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.

What to study next

Got this wrong? Here's your next step.

Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.

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FAQ

Questions learners often ask

What does this 1Z0-829 question test?

Working with Streams and Lambda Expressions — This question tests Working with Streams and Lambda Expressions — Read the scenario before looking for a memorised answer..

What is the correct answer to this question?

The correct answer is: opt.stream().map(String::toUpperCase).forEach(System.out::println); — Option C is correct because it converts the Optional to a Stream using opt.stream(), then applies map(String::toUpperCase) to transform the value, and finally uses forEach(System.out::println) to print it only if present. This approach leverages the Stream API's lazy evaluation and functional pipeline, which is the best practice for integrating Optional with streams.

What should I do if I get this 1Z0-829 question wrong?

Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.

Are there clue words in this question I should notice?

Yes — watch for: "best". Signals that multiple options may be partially correct. Choose the option that most directly solves the exact problem described, not the one that sounds most complete.

What is the key concept behind this question?

Read the scenario before looking for a memorised answer.

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Last reviewed: Jun 25, 2026

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