1Z0-1072-26 Networking Practice Question
You are managing an OCI VCN with CIDR block 10.0.0.0/16. You want to create a subnet that can hold up to 500 usable IP addresses. Which subnet CIDR block should you choose?
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
10.0.0.0/23
A /23 CIDR block provides 512 total IP addresses. In OCI, 2 IP addresses are reserved by Oracle (network address and broadcast-equivalent), and 3 are reserved for internal DHCP/router operations, leaving 507 usable IP addresses, which satisfies the requirement for 500.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
10.0.0.0/22
Why it's wrong here
A /22 subnet provides 1,024 total addresses, which is larger than necessary and wastes IP space.
- ✓
10.0.0.0/23
Why this is correct
A /23 subnet provides 512 total addresses (507 usable), satisfying the 500 usable requirement.
- ✗
10.0.1.0/24
Why it's wrong here
A /24 subnet provides 256 total addresses (approx 251 usable), which is less than 500.
- ✗
10.0.0.0/25
Why it's wrong here
A /25 subnet provides 128 total addresses.
Visual reference
About these practice questions
One of 524 original 1Z0-1072-26 practice questions on Courseiva, each with a full explanation and wrong-answer analysis — not exam dumps or protected exam content. Learn why practice questions differ from exam dumps →
JA
Written and reviewed by Johnson Ajibi, MSc IT Security
Senior Network & Security Engineer · founder of Courseiva
Last reviewed August 2026 · checked against the official Oracle exam blueprint
This 1Z0-1072-26 practice question is part of Courseiva's free Oracle certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 1Z0-1072-26 exam.