Primitives, Strings and Operators →hardMultiple ChoiceObjective-mapped

1Z0-811 Primitives, Strings and Operators Practice Question

What is the value of z after executing: int x = 3; int y = 2; int z = x++ * --y;

⚠ Common exam trap

Oracle often tests the difference between pre- and post-increment/decrement operators, and the trap here is that candidates mistakenly apply both operators to the original values or forget that post-increment returns the value before the increment.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

The expression `x++ * --y` uses post-increment on `x` and pre-decrement on `y`. Post-increment returns the original value of `x` (3) before incrementing it to 4. Pre-decrement decrements `y` from 2 to 1, then returns the new value (1). The multiplication is 3 * 1 = 3, which is assigned to `z`. So the correct answer is 3.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

✓
3
Why this is correct
x++ uses 3, --y yields 1, product = 3.
✗
6
Why it's wrong here
Incorrect order.
✗
4
Why it's wrong here
Not correct.
✗
2
Why it's wrong here
Miscalculation.

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1Z0-811 Primitives, Strings and Operators Practice Question

Why each option matters

Option-by-option breakdown

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