1Z0-811 Primitives, Strings and Operators Practice Question
What is the result of the following code snippet? int a = 5; int b = 2; double c = (double) (a / b); System.out.println(c);
⚠ Common exam trap
The trap here is that candidates often believe the cast to double will cause the division to be performed in floating-point, but the cast is applied after the integer division, so the fractional part is already lost.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
2.0
The expression `(a / b)` performs integer division, resulting in 2 (since both a and b are ints). The cast `(double)` is applied to the result of that integer division, converting the integer 2 to 2.0. The output is therefore 2.0.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
2
Why it's wrong here
c is double, so printed as 2.0.
- ✓
2.0
Why this is correct
a/b is integer division (2), then cast to double.
- ✗
Compilation error
Why it's wrong here
Code compiles and runs.
- ✗
2.5
Why it's wrong here
To get 2.5, cast before division: (double)a/b.
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