Question 17 of 509
Arrays and MethodsmediumMultiple ChoiceObjective-mapped

Quick Answer

The answer is 1 2 3 4 5 6. This output occurs because the varargs method `void print(int... nums)` treats the variable number of integer arguments as an array, printing each element separated by a space. When called twice—first with `print(1, 2, 3)` and then with `print(4, 5, 6)`—each invocation prints its own sequence, but since no newline is inserted between calls, the output concatenates into a single line. On the Oracle Java Foundations 1Z0-811 exam, varargs questions test your understanding of method overloading and array-like parameter handling; a common trap is forgetting that varargs can accept zero arguments, leading to empty output. To remember this, think of varargs as "variable arguments" that pack into an array automatically—just like a train coupling multiple cars without needing a separate loop to attach each one.

1Z0-811 Arrays and Methods Practice Question

This 1Z0-811 practice question tests your understanding of arrays and methods. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.

Exhibit

Refer to the exhibit.

public class VarargsExample {
    public static void main(String[] args) {
        print(1, 2, 3);
        print(new int[]{4, 5, 6});
    }
    public static void print(int... nums) {
        for (int n : nums) {
            System.out.print(n + " ");
        }
    }
}

What is the output?

Question 1mediummultiple choice
Full question →

Exhibit

Refer to the exhibit.

public class VarargsExample {
    public static void main(String[] args) {
        print(1, 2, 3);
        print(new int[]{4, 5, 6});
    }
    public static void print(int... nums) {
        for (int n : nums) {
            System.out.print(n + " ");
        }
    }
}

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

1 2 3 4 5 6

The code uses a varargs method `void print(int... nums)` which accepts zero or more int arguments. When called with `print(1, 2, 3)` and `print(4, 5, 6)`, each call prints the passed integers separated by spaces, resulting in "1 2 3 " and "4 5 6 " on the same line because there is no newline between calls. Thus the output is "1 2 3 4 5 6".

Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • 1 2 3

    Why it's wrong here

    The second call is also executed, so it prints more.

  • 1 2 3 4 5 6

    Why this is correct

    The first call prints 1 2 3 (with spaces), and the second call prints 4 5 6 on the same line.

    Related concept

    Read the scenario before looking for a memorised answer.

  • 1 2 3 4 5 6

    Why it's wrong here

    No newline is printed between calls because the print method does not output a newline.

  • Compilation error: ambiguous method call

    Why it's wrong here

    There is no ambiguity; the method can accept both forms.

Common exam traps

Common exam trap: answer the scenario, not the keyword

The trap here is that candidates often assume each method call starts on a new line, but the `print` method does not output a newline, so the output is concatenated on the same line.

Trap categories for this question

  • Command / output trap

    No newline is printed between calls because the print method does not output a newline.

Detailed technical explanation

How to think about this question

Varargs in Java are syntactic sugar for an array parameter; the compiler treats `int... nums` as `int[] nums` and creates an array from the arguments at the call site. Each call to `print` iterates over the array and prints each element followed by a space, but no newline is appended, so subsequent output continues on the same line. This behavior is defined by the Java Language Specification (JLS §8.4.1) and is commonly used in methods like `String.format` or logging frameworks where flexible argument counts are needed.

KKey Concepts to Remember

  • Read the scenario before looking for a memorised answer.
  • Find the constraint that changes the correct option.
  • Eliminate answers that are true in general but not in this case.

TExam Day Tips

  • Watch for words such as best, first, most likely and least administrative effort.
  • Review why wrong options are wrong, not only why the correct option is correct.

Key takeaway

Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Real-world example

How this comes up in practice

A practitioner preparing for the 1Z0-811 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.

What to study next

Got this wrong? Here's your next step.

Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.

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FAQ

Questions learners often ask

What does this 1Z0-811 question test?

Arrays and Methods — This question tests Arrays and Methods — Read the scenario before looking for a memorised answer..

What is the correct answer to this question?

The correct answer is: 1 2 3 4 5 6 — The code uses a varargs method `void print(int... nums)` which accepts zero or more int arguments. When called with `print(1, 2, 3)` and `print(4, 5, 6)`, each call prints the passed integers separated by spaces, resulting in "1 2 3 " and "4 5 6 " on the same line because there is no newline between calls. Thus the output is "1 2 3 4 5 6".

What should I do if I get this 1Z0-811 question wrong?

Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.

What is the key concept behind this question?

Read the scenario before looking for a memorised answer.

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Last reviewed: Jun 25, 2026

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This 1Z0-811 practice question is part of Courseiva's free Oracle certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 1Z0-811 exam.