1Z0-811 Primitives, Strings and Operators Practice Question
What is the output of the following? int x = Integer.MAX_VALUE; x++; System.out.println(x);
⚠ Common exam trap
The trap here is that candidates often expect an exception or a reset to zero, but Java silently handles integer overflow by wrapping around to the minimum value due to two's complement arithmetic.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
-2147483648
When x is Integer.MAX_VALUE (2147483647) and incremented, integer overflow occurs because Java int uses 32-bit two's complement representation. The value wraps around to the minimum int value, which is -2147483648, making D correct.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
2147483647
Why it's wrong here
Incremented, so not original.
- ✗
0
Why it's wrong here
Not zero.
- ✗
Exception
Why it's wrong here
No exception for overflow.
- ✓
-2147483648
Why this is correct
Overflow wraps to negative min.
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