1Z0-811 Java Basics and Syntax Practice Question
Exhibit
public class MyClass {
public static void main(String[] args) {
int num = 10;
if(num = 5) {
System.out.println("Five");
}
}
}Refer to the exhibit. What happens when you compile this code?
⚠ Common exam trap
Oracle often tests the distinction between using a final variable in a switch expression (allowed) versus attempting to reassign it inside the switch body (not allowed), leading candidates to incorrectly assume that final variables can be modified in any context.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
Compilation fails because num is final
The code fails to compile because the variable `num` is declared as `final`, meaning its value cannot be changed after initialization. The switch statement attempts to assign a new value to `num` in each case label (e.g., `case 1: num = 5;`), which results in a compilation error: cannot assign a value to a final variable. This is not a type mismatch; it is a violation of the final constraint.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
Compilation fails because of type mismatch
Why it's wrong here
Correct. The compilation fails because the final variable `num` cannot be reassigned. The error is a compilation error due to final variable modification.
- ✓
Compilation fails because num is final
Why this is correct
Incorrect. Although `num` is final, the specific error is a type mismatch because assigning to a final variable is illegal. The option's phrasing is too vague.
- ✗
Prints "Five"
Why it's wrong here
Incorrect. The code does not compile, so it cannot print "Five."
- ✗
Prints nothing
Why it's wrong here
Incorrect. The code does not compile, so it cannot print nothing.
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