Quick Answer
The answer is true. This is correct because the `==` operator in Java compares object references, not the actual string content, and due to string interning, both `s1` and `s2` point to the same literal `"Hello"` in the string constant pool. On the Oracle Java Foundations 1Z0-811 exam, this distinction between `==` and `.equals()` is a classic trap—many new developers assume `==` checks character equality, but it only checks if two references point to the exact same memory location. The exam frequently tests this with string literals versus `new String()` objects, where `new String("Hello") == new String("Hello")` would return `false`. To remember: think of `==` as asking “Are they the same object?” while `.equals()` asks “Do they have the same characters?” A useful mnemonic is “Double equals checks the address, dot equals checks the address book entry.”
This 1Z0-811 practice question tests your understanding of java basics and syntax. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Given two String objects s1 = "Hello" and s2 = "Hello", what does the expression (s1 == s2) return?
Compilation error
Why wrong: == can be used with object references.
false
Why wrong: Because of interning, both references point to the same object.
It depends on the JVM
Why wrong: Interning is guaranteed for string literals.
true
Both strings are string literals, so they are interned and share the same reference.
Answer choices
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
true
Option D is correct because the `==` operator compares object references, not string content. Since both `s1` and `s2` are string literals, Java's string interning ensures they refer to the same `String` object in the string constant pool, so `s1 == s2` returns `true`.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
For each option: why learners choose it and why it is or isn't the right answer here.
Compilation error
Why it's wrong here
== can be used with object references.
false
Why it's wrong here
Because of interning, both references point to the same object.
It depends on the JVM
Why it's wrong here
Interning is guaranteed for string literals.
true
Why this is correct
Both strings are string literals, so they are interned and share the same reference.
Related concept
Read the scenario before looking for a memorised answer.
Common exam traps
The trap here is that candidates often confuse reference equality (`==`) with value equality (`.equals()`), and incorrectly assume `==` always returns `false` for strings, forgetting that string literals are interned.
Detailed technical explanation
Under the hood, when the Java compiler encounters identical string literals, it stores only one instance in the string constant pool, and all references to that literal point to the same object. This interning mechanism is specified by the JLS and ensures that `==` returns `true` for identical string literals. A real-world scenario where this matters is when comparing strings read from user input or external sources, where `==` would fail and `.equals()` must be used instead.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
A practitioner preparing for the 1Z0-811 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
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FAQ
Java Basics and Syntax — This question tests Java Basics and Syntax — Read the scenario before looking for a memorised answer..
The correct answer is: true — Option D is correct because the `==` operator compares object references, not string content. Since both `s1` and `s2` are string literals, Java's string interning ensures they refer to the same `String` object in the string constant pool, so `s1 == s2` returns `true`.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Read the scenario before looking for a memorised answer.
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Last reviewed: Jun 25, 2026
This 1Z0-811 practice question is part of Courseiva's free Oracle certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 1Z0-811 exam.
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