1Z0-811 Java Basics and Syntax Practice Question
Given the loop: for (int i=0; i<5; i++) { if (i==2) continue; System.out.print(i); } What is the output?
⚠ Common exam trap
The 1Z0-811 exam often tests the distinction between 'continue' and 'break' in loops, and the trap here is that candidates may forget that 'continue' skips only the current iteration, not the entire loop, leading them to incorrectly include or exclude values.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
0134
The loop iterates i from 0 to 4. When i equals 2, the 'continue' statement skips the rest of that iteration, so 'System.out.print(i)' is not executed for i=2. Therefore, the output is 0, 1, 3, 4 concatenated as '0134'. Options A and C both display '0134' and are therefore correct. Option B shows '0124' (missing 3) and Option D shows '01234' (includes 2), both incorrect.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✓
0134
Why this is correct
Correct: 'continue' skips printing when i==2, so the output is 0134.
- ✗
0124
Why it's wrong here
Incorrect: Shows 0124, which erroneously includes 2 and misses 3.
- ✓
0134
Why this is correct
Correct: This option is identical to A and also shows the correct sequence 0134.
- ✗
01234
Why it's wrong here
Incorrect: Shows 01234, which includes i=2, not skipped.
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