Arrays and Methods →easyMultiple ChoiceObjective-mapped

1Z0-811 Arrays and Methods Practice Question

A method that calculates the average of an array of doubles is defined as:

public static double average(double[] values) {

double sum = 0;

for (double v : values) sum += v;
    return sum / values.length;
}

Which call is valid?

⚠ Common exam trap

Oracle often tests the difference between array initializer syntax and anonymous array creation, trapping candidates who think `{1.0, 2.0, 3.0}` can be used as a method argument without the `new double[]` prefix.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

double avg = average(new double[]{1.0, 2.0, 3.0});

The method `average(double[] values)` expects a single argument of type `double[]`. The expression `new double[]{1.0, 2.0, 3.0}` creates an anonymous array object that matches the parameter type exactly, so the call compiles and runs correctly.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

✗
double avg = average(1.0, 2.0);
Why it's wrong here
This passes two doubles, not an array, so it does not match the parameter type.
✓
double avg = average(new double[]{1.0, 2.0, 3.0});
Why this is correct
This creates a double array and passes it to the method.
✗
double avg = average(1.0, 2.0, 3.0);
Why it's wrong here
This syntax is only valid with varargs; the method expects an array, not a list of arguments.
✗
double avg = average({1.0, 2.0, 3.0});
Why it's wrong here
Anonymous array initializer syntax like {...} is only allowed in declaration statements, not as an argument.

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1Z0-811 Arrays and Methods Practice Question

Why each option matters

Option-by-option breakdown

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