Question 483 of 481
1Z0-811 Java Basics and Syntax Practice Question
A developer writes the following code: int x = 5; System.out.println(x++); What is the output?
⚠ Common exam trap
Oracle often tests the difference between post-increment and pre-increment operators, where candidates mistakenly think `x++` prints the incremented value (6) instead of the original value (5).
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
5
The expression `x++` is a post-increment operator, which returns the current value of `x` (5) before incrementing it. Therefore, `System.out.println(x++)` prints 5, and then `x` becomes 6. Option B is correct because the output is the original value of `x`.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
Compilation error
Why it's wrong here
Code compiles fine.
- ✓
5
Why this is correct
x++ returns 5, then x becomes 6.
- ✗
6
Why it's wrong here
This would be the result of ++x.
- ✗
Runtime exception
Why it's wrong here
No exception occurs.
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Last reviewed: Jun 30, 2026
This 1Z0-811 practice question is part of Courseiva's free Oracle certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 1Z0-811 exam.
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