1Z0-811 Java Basics and Syntax Practice Question
A developer writes: int x = 5; int y = x++ + ++x; What is the value of y after execution?
⚠ Common exam trap
The 1Z0-811 exam often tests the confusion between post-increment and pre-increment operators, where candidates mistakenly assume both increments use the same value or overlook the order of evaluation.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
12
The expression `int y = x++ + ++x;` involves post-increment and pre-increment operators. Initially, `x = 5`. In `x++`, the current value (5) is used, then `x` becomes 6. In `++x`, `x` is incremented to 7, then the new value (7) is used. So, `y = 5 + 7 = 12`. Option A is correct.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✓
12
Why this is correct
x++ uses 5 then increments to 6; ++x increments to 7 then uses 7; sum is 12.
- ✗
11
Why it's wrong here
This would be x++ + x++.
- ✗
10
Why it's wrong here
This would be ++x + ++x.
- ✗
Compilation error
Why it's wrong here
Expression is syntactically valid.
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