1Z0-811 Control Flow and Loops Practice Question
A developer writes a switch statement that checks the day of the week. The code uses fall-through to handle weekdays. What happens if a case does not end with a break?
⚠ Common exam trap
Test-takers frequently think missing a break causes a compilation error or runtime exception, but Java intentionally allows fall-through as a feature, and the Oracle Java Foundations exam tests whether you recognize this as normal behavior rather than an error.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
Execution continues to the next case
In Java, when a case in a switch statement does not end with a break statement, execution falls through to the next case, continuing until a break is encountered or the switch block ends. This is known as fall-through behavior, which the developer intentionally uses to handle weekdays collectively.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
The default case is executed
Why it's wrong here
Default runs only if matched, not due to fall-through.
- ✗
Compilation error
Why it's wrong here
Missing break is allowed, though often warned.
- ✗
Runtime exception is thrown
Why it's wrong here
No exception occurs.
- ✓
Execution continues to the next case
Why this is correct
Fall-through is intentional in some designs.
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