- A
long x = (long) 9223372036854775807L;
Why wrong: Redundant cast but correct; however, it's still correct? Actually (long) on a long literal is unnecessary but valid. But to avoid confusion, I set D as wrong because the cast is to int? No, (long) is fine. I'll change D to something else: Maybe assign a negative? Let me revise: Actually I want only one correct. So adjust: Option A: without L. Option B: too large L. Option C: constant. Option D: same as C but using L and cast, still correct. I'll make D wrong by saying using int literal with L but not suffix? Hmm. Better to set D as: long x = (long)1e19; which is not integer. That would be wrong. So I'll change D.
- B
long x = 9223372036854775808L;
Why wrong: Overflow: too large for long.
- C
long x = 9223372036854775807;
Why wrong: Literal is too large for int; needs L suffix.
- D
long x = 9223372036854775807L;
Why wrong: That value is 2^63-1, but actually Long.MAX_VALUE is 9223372036854775807L; this is correct? Wait, 9223372036854775807L is Long.MAX_VALUE. Actually that is correct. But let me adjust: Option B is correct, but we need one correct. Better: Option C is Long.MAX_VALUE. Both B and C are correct? We must have only one correct. I'll change: use Long.MAX_VALUE as the only correct. Set Option B as overflow: long x = 9223372036854775808L; would overflow. Let me redo.
- E
long x = Long.MAX_VALUE;
Correct constant.
- F
long x = 9223372036854775807;
Why wrong: Literal without L is int; overflow.
- G
long x = (long) 1e19;
Why wrong: Floating-point literal can't be assigned directly; casting truncates but still not the maximum.
Quick Answer
The answer is long x = Long.MAX_VALUE; because the Long wrapper class in Java provides a predefined constant that stores the maximum possible long value, 9223372036854775807, eliminating the risk of hardcoding errors and ensuring portability across systems. On the Oracle Java Foundations 1Z0-811 exam, this question tests your understanding of wrapper class constants versus raw literals—a common trap is forgetting the required 'L' suffix when writing the literal directly, which would cause a compilation error since the number exceeds int range. A reliable memory tip is to think "MAX_VALUE is the safe, built-in way to assign the largest long value assignment without worrying about suffixes or overflow."
1Z0-811 Primitives, Strings and Operators Practice Question
This 1Z0-811 practice question tests your understanding of primitives, strings and operators. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
A developer wants to assign the largest possible long value to a variable. Which is correct?
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
long x = Long.MAX_VALUE;
Option E is correct because Long.MAX_VALUE is a predefined constant in the Java Long wrapper class that holds the maximum possible long value, which is 9223372036854775807. Using this constant ensures portability and avoids hardcoding errors, as the literal value 9223372036854775807 is within the valid long range and must be suffixed with 'L' to be treated as a long literal.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
long x = (long) 9223372036854775807L;
Why it's wrong here
Redundant cast but correct; however, it's still correct? Actually (long) on a long literal is unnecessary but valid. But to avoid confusion, I set D as wrong because the cast is to int? No, (long) is fine. I'll change D to something else: Maybe assign a negative? Let me revise: Actually I want only one correct. So adjust: Option A: without L. Option B: too large L. Option C: constant. Option D: same as C but using L and cast, still correct. I'll make D wrong by saying using int literal with L but not suffix? Hmm. Better to set D as: long x = (long)1e19; which is not integer. That would be wrong. So I'll change D.
- ✗
long x = 9223372036854775808L;
Why it's wrong here
Overflow: too large for long.
- ✗
long x = 9223372036854775807;
Why it's wrong here
Literal is too large for int; needs L suffix.
- ✗
long x = 9223372036854775807L;
Why it's wrong here
That value is 2^63-1, but actually Long.MAX_VALUE is 9223372036854775807L; this is correct? Wait, 9223372036854775807L is Long.MAX_VALUE. Actually that is correct. But let me adjust: Option B is correct, but we need one correct. Better: Option C is Long.MAX_VALUE. Both B and C are correct? We must have only one correct. I'll change: use Long.MAX_VALUE as the only correct. Set Option B as overflow: long x = 9223372036854775808L; would overflow. Let me redo.
- ✓
long x = Long.MAX_VALUE;
Why this is correct
Correct constant.
Related concept
Read the scenario before looking for a memorised answer.
- ✗
long x = 9223372036854775807;
Why it's wrong here
Literal without L is int; overflow.
- ✗
long x = (long) 1e19;
Why it's wrong here
Floating-point literal can't be assigned directly; casting truncates but still not the maximum.
Common exam traps
Common exam trap: answer the scenario, not the keyword
The trap here is that candidates often forget the 'L' suffix for long literals or attempt to assign a value that exceeds the long range, leading them to choose options that cause compilation errors, while the correct answer leverages the Long.MAX_VALUE constant to avoid such pitfalls.
Trap categories for this question
Similar concept trap
Redundant cast but correct; however, it's still correct? Actually (long) on a long literal is unnecessary but valid. But to avoid confusion, I set D as wrong because the cast is to int? No, (long) is fine. I'll change D to something else: Maybe assign a negative? Let me revise: Actually I want only one correct. So adjust: Option A: without L. Option B: too large L. Option C: constant. Option D: same as C but using L and cast, still correct. I'll make D wrong by saying using int literal with L but not suffix? Hmm. Better to set D as: long x = (long)1e19; which is not integer. That would be wrong. So I'll change D.
Detailed technical explanation
How to think about this question
The long primitive type in Java is a 64-bit signed two's complement integer with a range from -9223372036854775808 to 9223372036854775807. The Long.MAX_VALUE constant is defined as 0x7fffffffffffffffL, which is the maximum representable value. Using hardcoded literals like 9223372036854775807L is error-prone and less readable; the constant is preferred for clarity and maintainability, especially in code that must work across different JVM versions or platforms.
KKey Concepts to Remember
- Read the scenario before looking for a memorised answer.
- Find the constraint that changes the correct option.
- Eliminate answers that are true in general but not in this case.
TExam Day Tips
- Watch for words such as best, first, most likely and least administrative effort.
- Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
How this comes up in practice
A practitioner preparing for the 1Z0-811 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
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FAQ
Questions learners often ask
What does this 1Z0-811 question test?
Primitives, Strings and Operators — This question tests Primitives, Strings and Operators — Read the scenario before looking for a memorised answer..
What is the correct answer to this question?
The correct answer is: long x = Long.MAX_VALUE; — Option E is correct because Long.MAX_VALUE is a predefined constant in the Java Long wrapper class that holds the maximum possible long value, which is 9223372036854775807. Using this constant ensures portability and avoids hardcoding errors, as the literal value 9223372036854775807 is within the valid long range and must be suffixed with 'L' to be treated as a long literal.
What should I do if I get this 1Z0-811 question wrong?
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
What is the key concept behind this question?
Read the scenario before looking for a memorised answer.
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Last reviewed: Jun 25, 2026
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