AWS provider Dynamic HCL Configuration Practice Question
When using 'for_each' on a list of strings, what must you do to ensure the configuration is stable?
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
Convert the list to a set
Using a list directly with for_each is often unstable if the list order changes. Converting it to a set with toset() ensures each item has a stable key.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
Use count instead
Why it's wrong here
count has its own stability issues.
- ✓
Convert the list to a set
Why this is correct
Converting to a set provides stable keys based on the value content.
- ✗
Use the index
Why it's wrong here
for_each doesn't use the index directly.
- ✗
Nothing, it's always stable
Why it's wrong here
List order changes can cause resource destruction/recreation.
About these practice questions
This AWS provider question is part of Courseiva's 193-question bank — original exam-style content with full explanations and wrong-answer analysis, never real exam questions or exam dumps. Learn why practice questions differ from exam dumps →
JA
Written and reviewed by Johnson Ajibi, MSc IT Security
Senior Network & Security Engineer · founder of Courseiva
Last reviewed August 2026 · checked against the official HashiCorp exam blueprint
This AWS provider practice question is part of Courseiva's free HashiCorp certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the AWS provider exam.