Question 1,768 of 2,152

EIGRP Troubleshooting →mediumMultiple ChoiceObjective-mapped

How to Read the Output of show ip eigrp neighbors

This 300-410 practice question tests your understanding of eigrp troubleshooting. Examine the command output carefully: the correct answer depends on what the output actually shows, not on general recall alone. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.

A network engineer runs the following command on Router R1:

R1# show ip eigrp neighbors

EIGRP-IPv4 Neighbors for AS(100) H Address Interface Hold Uptime SRTT RTO Q Seq (sec) (ms) Cnt Num 0 10.1.1.2 Gi0/0 13 00:12:34 12 200 0 45 1 10.2.2.2 Gi0/1 12 00:10:20 15 200 0 32 2 10.3.3.2 Gi0/2 14 00:08:15 18 200 0 28 3 10.4.4.2 Gi0/3 13 00:06:10 20 200 0 22

Based on this output, which statement is correct?

A
All four EIGRP neighbors are in the established state and exchanging routes.
All neighbors show a hold time, uptime, SRTT, RTO, and Q Cnt of 0, indicating a stable adjacency.
B
Neighbor 10.4.4.2 has a high SRTT of 20 ms, indicating a slow link.
Why wrong: An SRTT of 20 ms is normal and not considered high for EIGRP.
C
The Q Cnt of 0 means that there are 0 packets queued for retransmission, but this could indicate a problem.
Why wrong: A Q Cnt of 0 is normal and indicates no retransmissions are pending.
D
The neighbor on Gi0/3 has the lowest uptime, so it may be flapping.
Why wrong: An uptime of 6 minutes is not necessarily indicative of flapping; it could be a recent addition.

Full breakdown with real-world context →

Quick Answer

The answer is that all four EIGRP neighbors are in the established state and exchanging routes. This is correct because the output of show ip eigrp neighbors displays only neighbors that have successfully completed the neighbor adjacency process, and the key indicators here are the Q Cnt column showing zero for all entries, meaning no packets are queued waiting to be sent, combined with low SRTT and RTO values that reflect stable, bidirectional communication. On the Cisco CCNP ENARSI 300-410 exam, this command tests your ability to interpret EIGRP neighbor health and convergence; a common trap is assuming that a neighbor with a high SRTT or a non-zero Q Cnt is still fully operational, when in fact those values indicate congestion or retransmission issues. A useful memory tip is to remember that a zero in the Q Cnt column means “quiet and stable,” while any non-zero value signals a problem that could lead to a neighbor reset.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

All four EIGRP neighbors are in the established state and exchanging routes.

Option A is correct because all four neighbors show a Q Cnt of 0, which indicates no packets are queued for retransmission, and the Hold timers are within the default 15-second range, confirming that hello packets are being received regularly. The SRTT values are low (12-20 ms), and the RTO is consistent at 200 ms, which together with the established neighbor states (indicated by the 'H' column showing adjacency indices) confirms that all neighbors have successfully formed an adjacency and are exchanging routes in the EIGRP AS 100.

Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

✓
All four EIGRP neighbors are in the established state and exchanging routes.
Why this is correct
All neighbors show a hold time, uptime, SRTT, RTO, and Q Cnt of 0, indicating a stable adjacency.
Related concept
Read the scenario before looking for a memorised answer.
✗
Neighbor 10.4.4.2 has a high SRTT of 20 ms, indicating a slow link.
Why it's wrong here
An SRTT of 20 ms is normal and not considered high for EIGRP.
✗
The Q Cnt of 0 means that there are 0 packets queued for retransmission, but this could indicate a problem.
Why it's wrong here
A Q Cnt of 0 is normal and indicates no retransmissions are pending.
✗
The neighbor on Gi0/3 has the lowest uptime, so it may be flapping.
Why it's wrong here
An uptime of 6 minutes is not necessarily indicative of flapping; it could be a recent addition.

Common exam traps

Common exam trap: answer the scenario, not the keyword

Cisco often tests the misconception that a low uptime automatically indicates flapping, but in reality, uptime only shows how long the adjacency has been established, and without evidence of repeated resets or high sequence number gaps, it is not diagnostic of instability.

Detailed technical explanation

How to think about this question

In EIGRP, the SRTT (Smooth Round-Trip Time) is an exponentially weighted average of the time it takes to receive an acknowledgment for a reliable packet, and it directly influences the RTO (Retransmission Timeout), which is calculated as 6 times the SRTT (with a minimum of 200 ms). The Q Cnt (Queue Count) shows the number of packets waiting in the reliable transport queue; a value of 0 means all packets have been acknowledged, indicating a stable adjacency. The Hold timer decrements from 15 seconds (default) and is reset each time a hello is received; values around 12-14 seconds confirm timely hello reception.

KKey Concepts to Remember

Read the scenario before looking for a memorised answer.
Find the constraint that changes the correct option.
Eliminate answers that are true in general but not in this case.

TExam Day Tips

Watch for words such as best, first, most likely and least administrative effort.
Review why wrong options are wrong, not only why the correct option is correct.

Key takeaway

Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Real-world example

How this comes up in practice

A network engineer at a university connects two campus buildings via a fibre link. Both routers run OSPF, but no adjacency forms — even though both routers can ping each other. The engineer finds one router is in area 0 and the other in area 1. OSPF adjacency requires matching area numbers, hello/dead timers, and network type. IP reachability alone is not enough.

Quick reference

Routing Protocol Comparison

Protocol	Metric	Max Hops	Algorithm	Type
RIP v2	Hop count	15	Bellman-Ford	Distance vector
OSPF	Cost (bandwidth)	Unlimited	Dijkstra (SPF)	Link state
EIGRP	Composite metric	Unlimited	DUAL	Hybrid
IS-IS	Cost	Unlimited	Dijkstra	Link state
BGP	Policy / attributes	Unlimited	Path vector	Path vector

RIP's 15-hop limit makes it unsuitable for large networks. OSPF and EIGRP dominate modern enterprise deployments.

What to study next

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FAQ

Questions learners often ask

What does this 300-410 question test?

EIGRP Troubleshooting — This question tests EIGRP Troubleshooting — Read the scenario before looking for a memorised answer..

What is the correct answer to this question?

The correct answer is: All four EIGRP neighbors are in the established state and exchanging routes. — Option A is correct because all four neighbors show a Q Cnt of 0, which indicates no packets are queued for retransmission, and the Hold timers are within the default 15-second range, confirming that hello packets are being received regularly. The SRTT values are low (12-20 ms), and the RTO is consistent at 200 ms, which together with the established neighbor states (indicated by the 'H' column showing adjacency indices) confirms that all neighbors have successfully formed an adjacency and are exchanging routes in the EIGRP AS 100.

What should I do if I get this 300-410 question wrong?

Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.

What is the key concept behind this question?

Read the scenario before looking for a memorised answer.

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Same concept, more angles

1 more ways this is tested on 300-410

These questions test the same concept from different angles. Work through them to make sure you can recognise it however the exam phrases it.

Variation 1. A network engineer runs the following command on Router R1: R1# show ip eigrp neighbors detail EIGRP-IPv4 Neighbors for AS(100) H Address Interface Hold Uptime SRTT RTO Q Seq (sec) (ms) Cnt Num 0 10.1.1.2 Gi0/0 13 00:12:34 12 200 0 45 Version 12.0/2.0, Retrans: 0, Retries: 0, Restarts: 0 Topology ids from peer: 0 Passive interface: No Hello interval: 5 Hold time: 15 Based on this output, what is the problem?

hard

✓ A.The neighbor is operating normally with no issues.
B.The interface is configured as passive, preventing neighbor formation.
C.The neighbor has a high number of retransmissions.
D.The hold time of 15 seconds is too short and may cause flapping.

Why A: The output shows a fully established EIGRP neighbor adjacency with no errors. The 'Passive interface: No' confirms the interface is not configured as passive, the retransmission count is 0, and the hold time of 15 seconds is the default for a 5-second hello interval on high-speed interfaces. All metrics (SRTT, RTO, Q count, Seq Num) indicate stable operation, so there is no problem.

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