- A
10.0.1.50
Why wrong: 10.0.1.50 is on the 10.0.1.0/24 subnet, not the 10.0.0.0/24 subnet of the router.
- B
10.0.0.0
Why wrong: 10.0.0.0 is the network address and is reserved; it cannot be assigned to a host.
- C
10.0.0.50
10.0.0.50 is within the valid host range of 10.0.0.1 to 10.0.0.254 for the /24 subnet.
- D
10.0.0.255
Why wrong: 10.0.0.255 is the broadcast address for the /24 subnet and cannot be assigned to a host.
Question 652 of 1,020
Valid IP Address on a /24 Subnet: What's Allowed and What's Not
This 220-1201 practice question tests your understanding of ip addressing. This is a configuration task: choose the command set that satisfies every stated requirement. Small differences — like 'secret' vs 'password' or 'transport input ssh' vs 'all' — change whether the answer is correct. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
A technician is setting up a small office with 15 devices and needs to assign private IP addresses. The router's LAN interface is 10.0.0.1/24. Which of the following is a valid IP address for a workstation on this network?
Quick Answer
The correct answer is 10.0.0.50, because a /24 subnet mask defines the network as 10.0.0.0 with a usable host range of 10.0.0.1 through 10.0.0.254, and 10.0.0.50 falls squarely within that range without being reserved for the network ID or broadcast address. This concept tests your understanding of subnet boundaries and private IP addressing, a core objective on the CompTIA A+ Core 1 220-1201 exam. A common trap is assuming any address starting with 10 is valid, but the /24 mask strictly limits the valid IP address on a /24 subnet to the last octet between 1 and 254. Remember, the network address (ending in .0) and the broadcast address (ending in .255) are never assignable to a workstation. For a quick memory tip, think “.0 is the network, .255 is the shout, everything in between is what you’re about.”
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
10.0.0.50
Option C (10.0.0.50) is correct because the router's LAN interface is configured with the IP address 10.0.0.1 and a subnet mask of /24 (255.255.255.0). This defines the network as 10.0.0.0/24, which includes usable host addresses from 10.0.0.1 to 10.0.0.254. 10.0.0.50 falls within this valid host range.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
10.0.1.50
Why it's wrong here
10.0.1.50 is on the 10.0.1.0/24 subnet, not the 10.0.0.0/24 subnet of the router.
- ✗
10.0.0.0
Why it's wrong here
10.0.0.0 is the network address and is reserved; it cannot be assigned to a host.
- ✓
10.0.0.50
Why this is correct
10.0.0.50 is within the valid host range of 10.0.0.1 to 10.0.0.254 for the /24 subnet.
Related concept
Read the scenario before looking for a memorised answer.
- ✗
10.0.0.255
Why it's wrong here
10.0.0.255 is the broadcast address for the /24 subnet and cannot be assigned to a host.
Common exam traps
Common exam trap: answer the scenario, not the keyword
CompTIA often tests the distinction between network, broadcast, and usable host addresses within a given CIDR prefix, and the trap here is that candidates may forget that the first and last addresses in a subnet are reserved and not assignable to hosts.
Detailed technical explanation
How to think about this question
In a /24 subnet, the first address (e.g., 10.0.0.0) is the network identifier and the last address (e.g., 10.0.0.255) is the directed broadcast address, per RFC 919 and 922. The router's LAN interface at 10.0.0.1 is the default gateway for workstations; hosts must use an IP in the same subnet to communicate directly via ARP. A common real-world scenario is misconfiguring a static IP that falls outside the subnet, causing connectivity failure even if the physical link is up.
KKey Concepts to Remember
- Read the scenario before looking for a memorised answer.
- Find the constraint that changes the correct option.
- Eliminate answers that are true in general but not in this case.
TExam Day Tips
- Watch for words such as best, first, most likely and least administrative effort.
- Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
How this comes up in practice
A network engineer segments a warehouse floor into three subnets: 20 scanners, 5 printers, and 2 management hosts. Picking the wrong mask wastes addresses or leaves too few usable hosts. Exam questions test whether you can apply CIDR notation, calculate block size, and identify the correct usable-host range for a given prefix.
Visual reference
What to study next
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FAQ
Questions learners often ask
What does this 220-1201 question test?
IP Addressing — This question tests IP Addressing — Read the scenario before looking for a memorised answer..
What is the correct answer to this question?
The correct answer is: 10.0.0.50 — Option C (10.0.0.50) is correct because the router's LAN interface is configured with the IP address 10.0.0.1 and a subnet mask of /24 (255.255.255.0). This defines the network as 10.0.0.0/24, which includes usable host addresses from 10.0.0.1 to 10.0.0.254. 10.0.0.50 falls within this valid host range.
What should I do if I get this 220-1201 question wrong?
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
What is the key concept behind this question?
Read the scenario before looking for a memorised answer.
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Last reviewed: Jul 4, 2026
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