NSE7 Enterprise Firewall and VDOMs Practice Question
You run 'diagnose sys session filter dport 443' and see the following output: proto=6 proto_state=01 duration=3600 expire=3599 What does this indicate about the session?
⚠ Common exam trap
Many exam-takers confuse 'proto_state=01' with a half-open state (like SYN_RCVD) or misinterpret the 'duration' and 'expire' fields as indicating a blocked or expired session, when in fact they show a normal established TCP session with remaining lifetime.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
The session has been active for 1 hour and will expire in approximately 1 hour
The output shows 'duration=3600' and 'expire=3599', meaning the session has been active for 3600 seconds (1 hour) and will expire in 3599 seconds (approximately 1 hour). The 'proto=6' indicates TCP, and 'proto_state=01' is the TCP state code for an established connection (ESTABLISHED), not a half-open state. This is a normal, healthy session.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
The session is a UDP session for DNS
Why it's wrong here
proto=6 is TCP.
- ✗
The session is in a half-open state (SYN_RCVD)
Why it's wrong here
proto_state=01 typically indicates established, not half-open.
- ✗
The session is blocked because duration exceeds the timeout
Why it's wrong here
Duration is 3600 seconds, expire is 3599, so it's still active.
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JA
Written by Johnson Ajibi, MSc IT Security
Senior Network & Security Engineer · founder of Courseiva
This NSE7 practice question is part of Courseiva's free Fortinet certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the NSE7 exam.