Databricks-DE-Assoc Working with Lakeflow Jobs Practice Question
Exhibit
{
"job_id": 123,
"settings": {
"name": "Daily_Ingestion",
"tasks": [{
"task_key": "ingest",
"spark_jar_task": { "main_class_name": "com.example.Ingest" }
}],
"schedule": { "quartz_cron_expression": "0 0 12 * * ?" }
}
}Refer to the exhibit. When is this job scheduled to run?
⚠ Common exam trap
Candidates often misinterpret the Quartz cron syntax, specifically confusing the position of the hour and minute fields, or failing to account for the standard 12-hour clock format used in the expression.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
At 12:00 PM every day.
Understanding Quartz cron syntax is fundamental for scheduling jobs in Databricks. The expression '0 0 12 * * ?' maps to 12:00 PM (noon) daily. Being able to interpret and define schedules correctly is vital for data engineers to ensure that data pipelines run at the exact times required by business stakeholders, ensuring that data is fresh and available for reporting during peak business hours without unnecessary delays.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
Every minute at 12 seconds.
Why it's wrong here
The cron expression provided is '0 0 12 * * ?'. The first zero represents seconds, the second zero represents minutes, and 12 represents the hour. This specifies a exact time of 12:00:00, not a frequency of every minute, which would require an asterisk in the minute or second fields.
- ✓
At 12:00 PM every day.
Why this is correct
In Quartz cron syntax, 0 0 12 * * ? corresponds to seconds=0, minutes=0, hours=12, day-of-month=any, month=any, day-of-week=any. This results in the job triggering precisely at noon daily, which is a standard pattern for daily ingestion tasks requiring a single window of execution each day.
- ✗
Every 12 hours.
Why it's wrong here
A schedule of every 12 hours would typically be expressed as '0 0 0/12 * * ?' or similar variations. The current expression specifically targets the 12th hour of the day, rather than defining an interval that repeats throughout the day, thus it does not trigger every 12 hours.
- ✗
Every Monday at 12:00 AM.
Why it's wrong here
The asterisk in the day-of-month and month fields, combined with the question mark in the day-of-week field, indicates that it runs daily regardless of the day of the week. To target a specific day like Monday, the day-of-week field would need to be set to 'MON' instead of '?'.
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JA
Written and reviewed by Johnson Ajibi, MSc IT Security
Senior Network & Security Engineer · founder of Courseiva
Last reviewed September 2026 · checked against the official Databricks exam blueprint
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