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XK0-006 Troubleshooting Practice Question

An administrator wants to check the amount of free memory and swap usage on a system in a human-readable format. Which command should be used?

⚠ Common exam trap

XK0-006 often tests the assumption that any command with a -h flag produces human-readable output, when in fact -h means different things (or nothing) across tools like vmstat and iostat, leading candidates away from free -h.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

free -h

The free command displays total, used, and available physical memory and swap space, and the -h flag formats the output in human-readable units such as MiB and GiB. This directly satisfies the requirement to check free memory and swap usage in a readable format. It is the standard Linux utility for this purpose.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • ✓

    free -h

    Why this is correct

    'free -h' reads /proc/meminfo and prints total, used and available RAM alongside swap usage, with the -h flag scaling values into human-readable units such as MiB and GiB. This directly satisfies the requirement for readable free memory and swap figures.

  • ✗

    vmstat -h

    Why it's wrong here

    vmstat has no -h flag; it prints raw columns, and its free/swap figures are in kilobytes, not human-readable units. It is tempting because vmstat does report memory and swap statistics, making it the right choice when you need sampling intervals and paging activity rather than formatted totals.

  • ✗

    cat /proc/meminfo

    Why it's wrong here

    /proc/meminfo reports raw values in kibibytes with no unit conversion, so it is not human-readable. It is tempting because it is the authoritative kernel source for memory and swap figures, making it correct when scripting or parsing exact byte counts rather than reading formatted output.

  • ✗

    iostat -h

    Why it's wrong here

    iostat reports CPU and per-device disk I/O statistics; its -h flag only humanises those numbers, so it never reads /proc/meminfo or swap. It is tempting because it also displays human-readable output, but that is disk throughput, not free memory and swap.

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JA

Written and reviewed by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

Last reviewed September 2026 · checked against the official CompTIA exam blueprint

This XK0-006 practice question is part of Courseiva's free CompTIA certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the XK0-006 exam.