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XK0-006 Practice Question: A Linux server with the IP address 192.168.1.100…

A Linux server with the IP address 192.168.1.100 is unable to communicate with other hosts on the same subnet 192.168.1.0/24. The administrator can ping the loopback address, but pinging 192.168.1.1 (the default gateway) fails. The output of `ip a` shows the eth0 interface has the correct IP and netmask. Which troubleshooting step should be performed next?

⚠ Common exam trap

CompTIA often tests the misconception that a correct IP and netmask guarantee connectivity, leading candidates to jump to ARP or physical-layer checks, when the real issue is a missing or incorrect default route in the routing table.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

Check the routing table with ip route.

Since the server has the correct IP and netmask on eth0 but cannot ping the default gateway (192.168.1.1), the issue likely lies in the routing configuration. The `ip route` command displays the kernel routing table, including the default gateway entry; if the default route is missing or incorrect, traffic cannot reach the gateway. Checking the routing table is the logical next step before assuming physical or ARP-level problems.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • Check the ARP cache with arp -a.

    Why it's wrong here

    ARP may show incomplete entries but does not address routing configuration.

  • Replace the network cable.

    Why it's wrong here

    The interface is up with correct IP, so cable is likely fine.

  • Restart the network service.

    Why it's wrong here

    Restarting may not fix a missing route; verification of routing is more direct.

  • Check the routing table with ip route.

    Why this is correct

    The routing table will show if a default gateway is configured; missing gateway causes failure to reach local gateway.

Visual reference

192.168.1.0 /24 256 addresses (254 usable) 192.168.1.0 /25 Subnet A 128 addr (126 usable) 192.168.1.128 /25 Subnet B 128 addr (126 usable) Borrowing 1 bit from host portion creates 2 subnets (/25)

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JA

Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

This XK0-006 practice question is part of Courseiva's free CompTIA certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the XK0-006 exam.