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Automation, Orchestration, and ScriptinghardMultiple ChoiceObjective-mapped

XK0-006 Automation, Orchestration, and Scripting Practice Question

A Bash script uses getopts to parse command-line options. The options are -a (requires an argument) and -b (flag). Which code correctly implements this and stores the argument for -a in $optarg?

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

while getopts 'a:b' opt; do case $opt in a) arg=$OPTARG ;; b) flag=true ;; esac done

getopts uses the option string 'a:b' where 'a:' indicates -a requires an argument. The argument is stored in the variable $OPTARG (not $optarg).

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • while getopts 'a:b' opt; do case $opt in a) arg=$OPTARG ;; b) flag=true ;; esac done

    Why this is correct

    Correct. The colon after a indicates it requires an argument, and $OPTARG holds the value.

  • while getopts 'ab:' opt; do case $opt in a) arg=$OPTARG ;; b) flag=true ;; esac done

    Why it's wrong here

    Option string 'ab:' means -b requires argument, not -a.

  • while getopts 'a:b' opt; do case $opt in a) arg=$optarg ;; b) flag=true ;; esac done

    Why it's wrong here

    The variable is $OPTARG (uppercase), not $optarg.

  • while getopts ':a:b' opt; do case $opt in a) arg=$OPTARG ;; b) flag=true ;; esac done

    Why it's wrong here

    Leading colon suppresses errors but does not affect argument parsing.

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Written by Johnson Ajibi, MSc IT Security

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