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350-401 Practice Question: Runs the following command on Router R1: R1# show…

A network engineer runs the following command on Router R1:

R1# show ip eigrp interfaces

EIGRP-IPv4 Interfaces for AS(100)

Interface                   Peers    Xmit Queue   Mean   Pacing Time   Multicast    Pending

Un/Reliable SRTT Un/Reliable Flow Timer Routes Gi0/0 1 0/0 12 0/10 50 0 Gi0/1 1 0/0 15 0/10 55 0

Based on this output, what can be concluded?

⚠ Common exam trap

Cisco often tests the ability to interpret the 'show ip eigrp interfaces' output, specifically the 'Mean SRTT' column, and the trap here is that candidates confuse SRTT with interface bandwidth or fail to recognize that a higher SRTT means higher latency, not necessarily a problem with queue or pending routes.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

Interface Gi0/1 has higher latency than Gi0/0.

The 'Mean SRTT' (Smooth Round-Trip Time) column shows the average time in milliseconds for EIGRP packets to reach a neighbor and receive an acknowledgment. Gi0/1 has an SRTT of 15 ms, while Gi0/0 has an SRTT of 12 ms, indicating higher latency on Gi0/1. This directly correlates to the path's delay, which EIGRP uses in its composite metric calculation.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • ✓

    Interface Gi0/1 has higher latency than Gi0/0.

    Why this is correct

    The EIGRP interface output reports Mean SRTT (Smoothed Round-Trip Time) of 15 ms on Gi0/1 versus 12 ms on Gi0/0. A higher SRTT indicates a longer measured round-trip delay to the EIGRP neighbor, meaning Gi0/1 experiences higher latency. This is a direct metric for delay, not merely a configured value, so the conclusion is correct.

  • ✗

    Both interfaces have pending routes to send.

    Why it's wrong here

    The 'Pending Routes' column in 'show ip eigrp interfaces' represents the number of routes in the topology table that are waiting to be sent in a reliable EIGRP update to the neighbor. For both Gi0/0 and Gi0/1, this value is 0, meaning that no routes are queued for transmission. Thus, the statement that both interfaces have pending routes is false.

  • ✗

    The router is using EIGRP named mode.

    Why it's wrong here

    The output header reads 'EIGRP-IPv4 Interfaces for AS(100)', which is the format generated when EIGRP is configured in classic mode, where the autonomous system number is explicitly specified as 'AS(100)'. In named mode, the header would instead display the VRF and address-family context, such as 'EIGRP-IPv4 VR(default) Address-Family Interfaces'. Since the header shows 'AS(100)', the router is not using named mode.

  • ✗

    There is a queue backlog on Gi0/0.

    Why it's wrong here

    The 'Xmit Queue' column in the output shows the current and maximum size of the EIGRP transmission queue, formatted as 'current/max'. For Gi0/0, the value is '0/0', meaning the current queue depth is zero and no packets are waiting to be transmitted. This clearly indicates that there is no queue backlog on Gi0/0, making the statement incorrect.

Quick reference

Routing Protocol Comparison

ProtocolMetricMax HopsAlgorithmType
RIP v2Hop count15Bellman-FordDistance vector
OSPFCost (bandwidth)UnlimitedDijkstra (SPF)Link state
EIGRPComposite metricUnlimitedDUALHybrid
IS-ISCostUnlimitedDijkstraLink state
BGPPolicy / attributesUnlimitedPath vectorPath vector

RIP's 15-hop limit makes it unsuitable for large networks. OSPF and EIGRP dominate modern enterprise deployments.

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Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

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