This 350-401 practice question tests your understanding of acls and copp. This is a configuration task: choose the command set that satisfies every stated requirement. Small differences — like 'secret' vs 'password' or 'transport input ssh' vs 'all' — change whether the answer is correct. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Review the ACL configuration:
ip access-list extended TEST
permit tcp 192.168.1.0 0.0.0.255 any eq 80
permit tcp 192.168.1.0 0.0.0.255 any eq
443
deny ip any any
!
interface GigabitEthernet0/3
ip access-group TEST in
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
The deny ip any any is redundant because ACLs have an implicit deny at the end.
The ACL permits HTTP and HTTPS from 192.168.1.0/24 to any destination, but denies all other traffic. The configuration is syntactically correct.
Key principle: Count usable hosts — not total addresses — and remember that the network and broadcast addresses are not available to hosts in standard IPv4 subnets.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
✗
The ACL should use a wildcard mask of 255.255.255.0 instead of 0.0.0.255.
Why it's wrong here
Wildcard mask 0.0.0.255 is correct for matching 192.168.1.0/24.
✓
The deny ip any any is redundant because ACLs have an implicit deny at the end.
Why this is correct
The explicit deny is unnecessary but not incorrect; the implicit deny already blocks all other traffic.
The ACL must be applied outbound to filter incoming traffic.
Why it's wrong here
Inbound ACL filters traffic entering the interface; this is correct for incoming traffic.
✗
The ACL should use the keyword 'established' to allow return traffic.
Why it's wrong here
The ACL permits HTTP/HTTPS from the source; return traffic is handled by stateful inspection if configured, but not required here.
Common exam traps
Common exam trap: usable hosts are not the same as total addresses
Subnetting questions often tempt you into counting all addresses. In normal IPv4 subnets, the network and broadcast addresses are not usable host addresses.
Detailed technical explanation
How to think about this question
Subnetting questions test whether you can identify the network, broadcast address, usable range, mask and correct subnet. Slow down enough to calculate the block size correctly.
KKey Concepts to Remember
CIDR notation defines the prefix length.
Block size helps identify subnet boundaries.
Network and broadcast addresses are not usable hosts in normal IPv4 subnets.
The required host count determines the smallest suitable subnet.
TExam Day Tips
→Write the block size before choosing the subnet.
→Check whether the question asks for hosts, subnets or a specific address range.
→Do not confuse /24, /25, /26 and /27 host counts.
Key takeaway
Count usable hosts — not total addresses — and remember that the network and broadcast addresses are not available to hosts in standard IPv4 subnets.
Real-world example
How this comes up in practice
A small business has 20 workstations on the 192.168.1.0/24 network and one public IP from its ISP. The router uses PAT (NAT overload) so all 20 devices share one public address using different source ports. NAT questions test whether you understand the four address terms and which direction each translation applies.
Related glossary terms
Concepts from this question explained
These glossary pages explain the core terms tested in this 350-401 question in full detail.
Review block sizes, usable host formulas (2^n − 2), and how to find network and broadcast addresses for /24 through /30. Then practise related 350-401 subnetting questions on CIDR, address ranges, and subnet selection.
ACLs and CoPP — This question tests ACLs and CoPP — CIDR notation defines the prefix length..
What is the correct answer to this question?
The correct answer is: The deny ip any any is redundant because ACLs have an implicit deny at the end. — The ACL permits HTTP and HTTPS from 192.168.1.0/24 to any destination, but denies all other traffic. The configuration is syntactically correct.
What should I do if I get this 350-401 question wrong?
Review block sizes, usable host formulas (2^n − 2), and how to find network and broadcast addresses for /24 through /30. Then practise related 350-401 subnetting questions on CIDR, address ranges, and subnet selection.
What is the key concept behind this question?
CIDR notation defines the prefix length.
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Question Discussion
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