- A
All four EIGRP neighbors are in the established state and exchanging routes.
All neighbors show a hold time, uptime, SRTT, RTO, and Q Cnt of 0, indicating a stable adjacency.
- B
Neighbor 10.4.4.2 has a high SRTT of 20 ms, indicating a slow link.
Why wrong: An SRTT of 20 ms is normal and not considered high for EIGRP.
- C
The Q Cnt of 0 means that there are 0 packets queued for retransmission, but this could indicate a problem.
Why wrong: A Q Cnt of 0 is normal and indicates no retransmissions are pending.
- D
The neighbor on Gi0/3 has the lowest uptime, so it may be flapping.
Why wrong: An uptime of 6 minutes is not necessarily indicative of flapping; it could be a recent addition.
Quick Answer
The answer is that all four EIGRP neighbors are in the established state and exchanging routes. This is correct because the output of show ip eigrp neighbors displays only neighbors that have successfully completed the neighbor adjacency process, and the key indicators here are the Q Cnt column showing zero for all entries, meaning no packets are queued waiting to be sent, combined with low SRTT and RTO values that reflect stable, bidirectional communication. On the Cisco CCNP ENARSI 300-410 exam, this command tests your ability to interpret EIGRP neighbor health and convergence; a common trap is assuming that a neighbor with a high SRTT or a non-zero Q Cnt is still fully operational, when in fact those values indicate congestion or retransmission issues. A useful memory tip is to remember that a zero in the Q Cnt column means “quiet and stable,” while any non-zero value signals a problem that could lead to a neighbor reset.
300-410 EIGRP Troubleshooting Practice Question
This 300-410 practice question tests your understanding of eigrp troubleshooting. Examine the command output carefully: the correct answer depends on what the output actually shows, not on general recall alone. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
A network engineer runs the following command on Router R1:
R1# show ip eigrp neighbors
EIGRP-IPv4 Neighbors for AS(100) H Address Interface Hold Uptime SRTT RTO Q Seq (sec) (ms) Cnt Num 0 10.1.1.2 Gi0/0 13 00:12:34 12 200 0 45 1 10.2.2.2 Gi0/1 12 00:10:20 15 200 0 32 2 10.3.3.2 Gi0/2 14 00:08:15 18 200 0 28 3 10.4.4.2 Gi0/3 13 00:06:10 20 200 0 22
Based on this output, which statement is correct?
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
All four EIGRP neighbors are in the established state and exchanging routes.
The show ip eigrp neighbors command displays all EIGRP neighbors. The 'H' column shows the order in which neighbors were learned. The 'Hold' column shows the remaining hold time in seconds. All neighbors are in a stable state with low SRTT and RTO values, and no outstanding packets (Q Cnt = 0). The output indicates that all four neighbors are fully operational.
Key principle: OSPF neighbour adjacency depends on matching area, hello/dead timers, network type, and authentication — IP reachability alone is not enough.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✓
All four EIGRP neighbors are in the established state and exchanging routes.
Why this is correct
All neighbors show a hold time, uptime, SRTT, RTO, and Q Cnt of 0, indicating a stable adjacency.
Related concept
OSPF neighbours must agree on key parameters.
- ✗
Neighbor 10.4.4.2 has a high SRTT of 20 ms, indicating a slow link.
Why it's wrong here
An SRTT of 20 ms is normal and not considered high for EIGRP.
- ✗
The Q Cnt of 0 means that there are 0 packets queued for retransmission, but this could indicate a problem.
Why it's wrong here
A Q Cnt of 0 is normal and indicates no retransmissions are pending.
- ✗
The neighbor on Gi0/3 has the lowest uptime, so it may be flapping.
Why it's wrong here
An uptime of 6 minutes is not necessarily indicative of flapping; it could be a recent addition.
Common exam traps
Common exam trap: OSPF can fail even when IP connectivity looks correct
OSPF neighbour formation depends on matching areas, timers, network type, authentication and passive-interface behaviour. Do not choose an answer only because the devices can ping.
Detailed technical explanation
How to think about this question
OSPF questions usually test the details that control adjacency and route selection. Read the neighbour state, area, router ID and interface configuration before deciding what is wrong.
KKey Concepts to Remember
- OSPF neighbours must agree on key parameters.
- Router ID selection can affect neighbour relationships and LSDB output.
- OSPF cost influences the preferred path.
- A route can appear in OSPF information but not become the installed route.
TExam Day Tips
- Check area mismatch first when OSPF adjacency fails.
- Review passive interfaces when a network is advertised but no neighbour forms.
- Use show ip ospf neighbor and show ip route clues carefully.
Key takeaway
OSPF neighbour adjacency depends on matching area, hello/dead timers, network type, and authentication — IP reachability alone is not enough.
Real-world example
How this comes up in practice
A network engineer at a university connects two campus buildings via a fibre link. Both routers run OSPF, but no adjacency forms — even though both routers can ping each other. The engineer finds one router is in area 0 and the other in area 1. OSPF adjacency requires matching area numbers, hello/dead timers, and network type. IP reachability alone is not enough.
What to study next
Got this wrong? Here's your next step.
Review OSPF neighbour requirements — matching area type, hello and dead timers, network type, stub flags, and authentication. Study show ip ospf neighbor states (INIT, 2-WAY, FULL). Then practise related 300-410 OSPF questions on adjacency and route selection.
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FAQ
Questions learners often ask
What does this 300-410 question test?
EIGRP Troubleshooting — This question tests EIGRP Troubleshooting — OSPF neighbours must agree on key parameters..
What is the correct answer to this question?
The correct answer is: All four EIGRP neighbors are in the established state and exchanging routes. — The show ip eigrp neighbors command displays all EIGRP neighbors. The 'H' column shows the order in which neighbors were learned. The 'Hold' column shows the remaining hold time in seconds. All neighbors are in a stable state with low SRTT and RTO values, and no outstanding packets (Q Cnt = 0). The output indicates that all four neighbors are fully operational.
What should I do if I get this 300-410 question wrong?
Review OSPF neighbour requirements — matching area type, hello and dead timers, network type, stub flags, and authentication. Study show ip ospf neighbor states (INIT, 2-WAY, FULL). Then practise related 300-410 OSPF questions on adjacency and route selection.
What is the key concept behind this question?
OSPF neighbours must agree on key parameters.
About these practice questions
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Same concept, more angles
1 more ways this is tested on 300-410
These questions test the same concept from different angles. Work through them to make sure you can recognise it however the exam phrases it.
Variation 1. A network engineer runs the following command on Router R1: R1# show ip eigrp neighbors detail EIGRP-IPv4 Neighbors for AS(100) H Address Interface Hold Uptime SRTT RTO Q Seq (sec) (ms) Cnt Num 0 10.1.1.2 Gi0/0 13 00:12:34 12 200 0 45 Version 12.0/2.0, Retrans: 0, Retries: 0, Restarts: 0 Topology ids from peer: 0 Passive interface: No Hello interval: 5 Hold time: 15 Based on this output, what is the problem?
hard- ✓ A.The neighbor is operating normally with no issues.
- B.The interface is configured as passive, preventing neighbor formation.
- C.The neighbor has a high number of retransmissions.
- D.The hold time of 15 seconds is too short and may cause flapping.
Why A: The detail output shows the neighbor is up with normal parameters. However, the 'Passive interface: No' indicates that the interface is not configured as passive, which is expected for forming neighbors. There is no problem evident; the neighbor is functioning correctly.
Last reviewed: Jun 18, 2026
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