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300-410 Practice Question: Runs the following command to troubleshoot a…

A network engineer runs the following command to troubleshoot a Route Summarization issue:

R1# show ip eigrp topology 10.0.0.0/16

IP-EIGRP topology entry for 10.0.0.0/16 State is Passive, Query origin flag is 1, 1 Successor(s), FD is 128576 Routing Descriptor Blocks:

10.1.1.2 (Serial0/0/0), from 10.1.1.2, Send flag is 0x0

Composite metric is (128576/156160), Route is Internal Vector metric: Minimum bandwidth is 10000 Kbit Total delay is 2000 microseconds Reliability is 255/255 Load is 1/255 Minimum MTU is 1500 Hop count is 2

What does this output indicate?

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

The summary route 10.0.0.0/16 is installed in the routing table and reachable via 10.1.1.2.

This output shows the EIGRP topology table entry for the summary route 10.0.0.0/16. The state is Passive, meaning the route is stable and reachable. The presence of a successor and the metric details indicate that the summary route is being advertised and learned via EIGRP.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • The summary route 10.0.0.0/16 is installed in the routing table and reachable via 10.1.1.2.

    Why this is correct

    The output shows a valid successor and passive state, confirming the route is installed and reachable.

  • The summary route is in active state, indicating a query is in progress.

    Why it's wrong here

    The state is Passive, not Active.

  • The summary route is not being advertised because the FD is too high.

    Why it's wrong here

    The FD value is normal and does not prevent advertisement.

  • The summary route is learned via redistribution, not summarization.

    Why it's wrong here

    The route is marked as Internal, indicating it is from within the same EIGRP AS.

Visual reference

PC R1 R2 R3 Server hop 1 hop 2 hop 3 RIP metric = 3 hops — lowest hop count wins

Quick reference

Routing Protocol Comparison

ProtocolMetricMax HopsAlgorithmType
RIP v2Hop count15Bellman-FordDistance vector
OSPFCost (bandwidth)UnlimitedDijkstra (SPF)Link state
EIGRPComposite metricUnlimitedDUALHybrid
IS-ISCostUnlimitedDijkstraLink state
BGPPolicy / attributesUnlimitedPath vectorPath vector

RIP's 15-hop limit makes it unsuitable for large networks. OSPF and EIGRP dominate modern enterprise deployments.

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JA

Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

This 300-410 practice question is part of Courseiva's free Cisco certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 300-410 exam.