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300-410 Practice Question: Runs the following command to troubleshoot OSPF…
A network engineer runs the following command to troubleshoot OSPF route redistribution:
R1# show ip ospf database external 5.5.5.5
OSPF Router with ID (1.1.1.1) (Process ID 1)
Type-5 AS External Link States
LS age: 120 Options: (No TOS-capability, DC, Upward) LS Type: AS External Link Link State ID: 5.5.5.5 (External Network Number) Advertising Router: 3.3.3.3 LS Seq Number: 80000001 Checksum: 0xABCD Length: 36 Network Mask: /32 Metric Type: 2 (Larger than any link state path) TOS: 0 Metric: 20 Forward Address: 0.0.0.0 External Route Tag: 0
What does this output indicate?
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
The route was redistributed into OSPF by router 3.3.3.3 with a metric of 20.
The output shows an OSPF Type 5 External LSA for prefix 5.5.5.5/32, advertised by router 3.3.3.3 with a metric type E2 and metric 20.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
The prefix 5.5.5.5/32 is a network inside the OSPF domain.
Why it's wrong here
Type 5 LSAs are for external routes redistributed into OSPF.
- ✓
The route was redistributed into OSPF by router 3.3.3.3 with a metric of 20.
Why this is correct
The LSA is Type-5, advertising router is 3.3.3.3, metric type E2 with metric 20.
- ✗
The forward address indicates the next-hop is 5.5.5.5.
Why it's wrong here
The forward address is 0.0.0.0, meaning the next-hop is the advertising router.
- ✗
This is a Type 4 Summary ASBR LSA.
Why it's wrong here
The LS Type is AS External Link, which is Type 5.
Visual reference
Quick reference
Routing Protocol Comparison
| Protocol | Metric | Max Hops | Algorithm | Type |
|---|---|---|---|---|
| RIP v2 | Hop count | 15 | Bellman-Ford | Distance vector |
| OSPF | Cost (bandwidth) | Unlimited | Dijkstra (SPF) | Link state |
| EIGRP | Composite metric | Unlimited | DUAL | Hybrid |
| IS-IS | Cost | Unlimited | Dijkstra | Link state |
| BGP | Policy / attributes | Unlimited | Path vector | Path vector |
RIP's 15-hop limit makes it unsuitable for large networks. OSPF and EIGRP dominate modern enterprise deployments.
Go deeper
Related to this question
Learn chapter
Introduction to ENARSI Exam and Network Fundamentals
Key term
Route Redistribution Between Protocols
Route redistribution between protocols is the process of taking routes learned from one routing protocol and injecting them into another routing protocol so that networks using different protocols can communicate.
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JA
Written by Johnson Ajibi, MSc IT Security
Senior Network & Security Engineer · founder of Courseiva
This 300-410 practice question is part of Courseiva's free Cisco certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 300-410 exam.