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300-410 Practice Question: Runs the following command on Router R1: R1# show…

A network engineer runs the following command on Router R1:

R1# show ip ospf neighbor

Neighbor ID     Pri   State           Dead Time   Address         Interface
192.168.1.2      1   FULL/DR         00:00:35    192.168.1.2     Gi0/0
192.168.2.2      1   2WAY/DROTHER    00:00:38    192.168.2.2     Gi0/1
10.10.10.2       1   FULL/BDR        00:00:32    10.10.10.2      Gi0/2

Based on this output, what is a potential issue?

⚠ Common exam trap

Cisco often tests the misconception that the 2WAY state is always a problem, but in reality it is a normal and expected state for DROTHER neighbors on broadcast multi-access networks, and candidates must recognize that only the DR and BDR should be in FULL state with all neighbors.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

All OSPF neighbors are in appropriate states for their roles.

The output shows normal OSPF neighbor states for a multi-access network. The DR (192.168.1.2) is in FULL/DR state, the BDR (10.10.10.2) is in FULL/BDR state, and the DROTHER (192.168.2.2) is in 2WAY/DROTHER state, which is expected for a non-DR/non-BDR router on a broadcast multi-access segment. The 2WAY state is a valid and stable state for DROTHER neighbors, indicating that they have exchanged Hello packets and are aware of each other but do not form full adjacency with each other.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • Neighbor 192.168.2.2 is stuck in 2WAY state, indicating a problem.

    Why it's wrong here

    2WAY is a normal state for DROTHER neighbors.

  • The DR election is incomplete on Gi0/0.

    Why it's wrong here

    The state is FULL/DR, which is correct.

  • All OSPF neighbors are in appropriate states for their roles.

    Why this is correct

    Each neighbor is in the correct state based on its role (DR, BDR, DROTHER).

  • Neighbor 10.10.10.2 should be in FULL/DR state.

    Why it's wrong here

    It is the BDR, so FULL/BDR is correct.

Visual reference

R1 R2 R3 R4 10 100 10 100 OSPF picks R1→R2→R4 (cost 20) over R1→R3→R4 (cost 200)

Quick reference

Routing Protocol Comparison

ProtocolMetricMax HopsAlgorithmType
RIP v2Hop count15Bellman-FordDistance vector
OSPFCost (bandwidth)UnlimitedDijkstra (SPF)Link state
EIGRPComposite metricUnlimitedDUALHybrid
IS-ISCostUnlimitedDijkstraLink state
BGPPolicy / attributesUnlimitedPath vectorPath vector

RIP's 15-hop limit makes it unsuitable for large networks. OSPF and EIGRP dominate modern enterprise deployments.

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JA

Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

This 300-410 practice question is part of Courseiva's free Cisco certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 300-410 exam.