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300-410 Practice Question: Runs the following command to troubleshoot a…
A network engineer runs the following command to troubleshoot a Device Access Control issue:
R1# show ip eigrp topology 10.10.10.0/24 all-links
P 10.10.10.0/24, 1 successors, FD is 1310720 via 10.1.1.2 (1310720/1310720), GigabitEthernet0/0 via 10.1.2.2 (1310720/1310720), GigabitEthernet0/1
What does this output indicate?
⚠ Common exam trap
Cisco often tests the distinction between equal-cost paths (same FD) and feasible successors (RD < FD), leading candidates to mistakenly label an equal-cost path as a feasible successor or assume only the first path is used.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
There are two equal-cost paths to 10.10.10.0/24, and EIGRP will load balance across them.
The output shows two EIGRP routes to 10.10.10.0/24 with identical Feasible Distances (FD) of 1310720, indicating equal-cost paths. EIGRP installs up to four equal-cost routes by default and performs per-destination load balancing across them, so both paths are active and used.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✓
There are two equal-cost paths to 10.10.10.0/24, and EIGRP will load balance across them.
Why this is correct
Both paths have the same FD and RD, making them equal-cost successors; EIGRP will install both and load balance.
- ✗
Only the first path via 10.1.1.2 is installed because the second path has a higher FD.
Why it's wrong here
Both paths have identical FD values, so both are considered equal-cost successors.
- ✗
The path via 10.1.2.2 is a feasible successor but is not used because it has a higher RD.
Why it's wrong here
The RD is identical to the FD, so it is a successor, not just a feasible successor.
- ✗
The router has no route to 10.10.10.0/24 because the FD is the same as the RD.
Why it's wrong here
The route is present (indicated by 'P'), and the FD/RD equality indicates a valid path.
Quick reference
Routing Protocol Comparison
| Protocol | Metric | Max Hops | Algorithm | Type |
|---|---|---|---|---|
| RIP v2 | Hop count | 15 | Bellman-Ford | Distance vector |
| OSPF | Cost (bandwidth) | Unlimited | Dijkstra (SPF) | Link state |
| EIGRP | Composite metric | Unlimited | DUAL | Hybrid |
| IS-IS | Cost | Unlimited | Dijkstra | Link state |
| BGP | Policy / attributes | Unlimited | Path vector | Path vector |
RIP's 15-hop limit makes it unsuitable for large networks. OSPF and EIGRP dominate modern enterprise deployments.
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Written by Johnson Ajibi, MSc IT Security
Senior Network & Security Engineer · founder of Courseiva
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