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300-410 OSPF neighbor states Practice Question

A network engineer runs the following command on Router R1:

R1# show ip ospf neighbor

Neighbor ID     Pri   State           Dead Time   Address         Interface
192.168.1.2     1     FULL/DR        00:00:35    10.1.1.2        GigabitEthernet0/0
192.168.2.2     1     2WAY/DROTHER   00:00:32    10.2.2.2        GigabitEthernet0/1
192.168.3.2     1     FULL/BDR       00:00:38    10.3.3.2        GigabitEthernet0/2

Based on this output, what is a potential issue?

⚠ Common exam trap

Candidates often incorrectly assume that any state other than FULL indicates a problem. However, in OSPF broadcast multi-access networks, the 2WAY state between DROTHER routers is normal and does not indicate an issue.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

All neighbors are in FULL state, indicating no issues.

The output shows normal OSPF neighbor states on a broadcast multi-access network. The neighbor on Gi0/1 is in the 2WAY/DROTHER state, which is expected for non-DR/BDR routers. The neighbors on Gi0/0 and Gi0/2 are in FULL state (DR and BDR respectively). All states are valid, so there is no issue.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • ✗

    The neighbor on Gi0/1 is not forming a full adjacency because it is in 2WAY state.

    Why it's wrong here

    2WAY/DROTHER is the expected state between non-DR/BDR routers on a broadcast segment; full adjacency forms only with the DR and BDR. It tempts because 2WAY on a point-to-point link would indicate a genuine adjacency failure, so the state looks alarming without checking network type.

  • ✗

    The neighbor on Gi0/0 is the DR, which is causing high CPU usage.

    Why it's wrong here

    DR status on Gi0/0 is normal and does not by itself cause high CPU; DR election follows priority and router ID. It tempts because a flapping DR can trigger repeated SPF recalculations and CPU spikes, so linking DR behaviour to CPU load is reasonable when instability is observed.

  • ✗

    The neighbor on Gi0/2 is the BDR, which is a problem because it should be the DR.

    Why it's wrong here

    A BDR on Gi0/2 is normal; DR/BDR election depends on priority and router ID, and any non-DR router legitimately becomes BDR. It tempts because DR/BDR roles are frequently misconfigured, so checking which router holds which role is a sensible troubleshooting step when adjacency problems appear.

  • ✓

    All neighbors are in FULL state, indicating no issues.

    Why this is correct

    The 2WAY/DROTHER state on GigabitEthernet0/1 is normal for a non-DR/BDR router on a broadcast segment, so no adjacency fault exists; the two FULL adjacencies confirm working OSPF relationships, meaning the output shows no actual problem.

Visual reference

R1 R2 R3 R4 10 100 10 100 OSPF picks R1→R2→R4 (cost 20) over R1→R3→R4 (cost 200)

Quick reference

Routing Protocol Comparison

ProtocolMetricMax HopsAlgorithmType
RIP v2Hop count15Bellman-FordDistance vector
OSPFCost (bandwidth)UnlimitedDijkstra (SPF)Link state
EIGRPComposite metricUnlimitedDUALHybrid
IS-ISCostUnlimitedDijkstraLink state
BGPPolicy / attributesUnlimitedPath vectorPath vector

RIP's 15-hop limit makes it unsuitable for large networks. OSPF and EIGRP dominate modern enterprise deployments.

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JA

Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

This 300-410 practice question is part of Courseiva's free Cisco certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 300-410 exam.