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300-410 Practice Question: Runs the following command on Router R1: R1# show…

A network engineer runs the following command on Router R1:

R1# show ip eigrp neighbors

EIGRP-IPv4 Neighbors for AS(100) H Address Interface Hold Uptime SRTT RTO Q Seq (sec) (ms) Cnt Num 0 10.1.1.2 Gi0/0 13 00:12:34 1 200 0 45 1 10.2.2.2 Gi0/1 12 00:11:20 2 200 0 67 2 10.3.3.2 Gi0/2 10 00:10:15 1 200 0 89

Based on this output, which statement is correct?

⚠ Common exam trap

Cisco often tests the misconception that a lower hold timer or a higher sequence number indicates a problem, when in fact these values are normal operational metrics that do not imply faults unless they deviate significantly from expected baselines.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

All EIGRP neighbors are fully operational with no issues.

The output shows all three EIGRP neighbors with hold timers above 0, low SRTT values (1-2 ms), RTO at 200 ms, and a Q count of 0, indicating no queued packets. These metrics confirm that the neighbors are fully operational and stable, with no packet loss, congestion, or routing issues.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • ✓

    All EIGRP neighbors are fully operational with no issues.

    Why this is correct

    The queue count is zero for every neighbour, confirming no EIGRP packets are awaiting transmission, and each adjacency has been up for over ten minutes with stable sequence numbers. The hold timers remain well above zero, so no peer is expiring. This satisfies the stem's requirement of identifying a healthy, converged EIGRP topology.

  • ✗

    The neighbor on Gi0/2 is experiencing packet loss because its hold timer is 10 seconds.

    Why it's wrong here

    A 10-second hold timer is normal EIGRP behaviour, counting down from 15 between hellos; it does not indicate packet loss. Loss would show as a rising Q Count or retransmissions. It tempts because a low countdown looks alarming, but hold time simply reflects elapsed time since the last hello.

  • ✗

    The neighbor on Gi0/0 has a high SRTT, indicating congestion.

    Why it's wrong here

    An SRTT of 1 ms is excellent, not high; congestion would appear as an elevated SRTT with a correspondingly larger RTO. It tempts because SRTT measures round-trip time, so candidates assume any value signals delay, but 1 ms is near-instant.

  • ✗

    The neighbor on Gi0/1 has a sequence number of 67, which is higher than others, indicating a routing loop.

    Why it's wrong here

    The Seq Num column tracks the last sequence number received from that neighbour; differing values across neighbours are expected and unrelated to loops. Loops would surface as route flapping or stuck-in-active states. It tempts because a larger number looks anomalous, but each neighbour maintains its own sequence.

Quick reference

Routing Protocol Comparison

ProtocolMetricMax HopsAlgorithmType
RIP v2Hop count15Bellman-FordDistance vector
OSPFCost (bandwidth)UnlimitedDijkstra (SPF)Link state
EIGRPComposite metricUnlimitedDUALHybrid
IS-ISCostUnlimitedDijkstraLink state
BGPPolicy / attributesUnlimitedPath vectorPath vector

RIP's 15-hop limit makes it unsuitable for large networks. OSPF and EIGRP dominate modern enterprise deployments.

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Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

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