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200-901 Practice Question: Refer to the exhibit

Exhibit

R1# show ip route
Codes: L - local, C - connected, S - static, R - RIP, O - OSPF, B - BGP
       D - EIGRP, EX - EIGRP external, N - NAPT
Gateway of last resort is 10.0.0.1
     10.0.0.0/8 is variably subnetted, 2 subnets
C       10.0.0.0/24 is directly connected, GigabitEthernet0/0
S       10.0.1.0/24 [1/0] via 10.0.0.2

Refer to the exhibit. A developer is parsing the output of 'show ip route' using Python. Which regular expression would extract the prefix '10.0.1.0/24'?

⚠ Common exam trap

Cisco often tests the distinction between capturing only the IP address versus the full CIDR prefix, leading candidates to pick options that omit the subnet mask (like Option B) or use overly broad patterns (like Option C) that match unintended fields.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

r'^S\s+(\d+\.\d+\.\d+\.\d+/\d+)'

The regex `^S\s+(\d+\.\d+\.\d+\.\d+/\d+)` matches lines starting with 'S' (static route) followed by whitespace, then captures the entire prefix including both the IP address and subnet mask in CIDR notation (e.g., 10.0.1.0/24). This ensures the extracted string is exactly the prefix as it appears in the 'show ip route' output.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • r'^S\s+(\d+\/\d+)'

    Why it's wrong here

    Only captures network and mask without dots, e.g., '10/24'.

  • r'^S.*(\d+\.\d+\.\d+\.\d+)'

    Why it's wrong here

    Captures IP without subnet mask, and .* may skip prefix.

  • r'S\s+(\S+)'

    Why it's wrong here

    Lacks start anchor and may match other lines with 'S'.

  • r'^S\s+(\d+\.\d+\.\d+\.\d+/\d+)'

    Why this is correct

    Correctly anchors at line start and captures prefix.

Visual reference

192.168.1.0 /24 256 addresses (254 usable) 192.168.1.0 /25 Subnet A 128 addr (126 usable) 192.168.1.128 /25 Subnet B 128 addr (126 usable) Borrowing 1 bit from host portion creates 2 subnets (/25)

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JA

Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

This 200-901 practice question is part of Courseiva's free Cisco certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 200-901 exam.