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200-901 Software Development and Design Practice Question

In Python, which of the following is a valid way to define a function that accepts a variable number of positional arguments?

⚠ Common exam trap

Cisco often tests the distinction between `*args` (positional) and `**kwargs` (keyword) and may include syntactically invalid options like `args*` to catch candidates who misremember the asterisk placement.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

def func(*args):

In Python, the `*args` syntax in a function definition allows the function to accept a variable number of positional arguments. The asterisk (`*`) collects all extra positional arguments into a tuple named `args`, enabling flexible argument handling.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

✗
def func(args):
Why it's wrong here
This expects a single argument; no variable number.
✗
def func(args*):
Why it's wrong here
Invalid syntax; the asterisk must precede the parameter name.
✗
def func(**kwargs):
Why it's wrong here
**kwargs collects keyword arguments, not positional.
✓
def func(*args):
Why this is correct
Yes, *args collects extra positional arguments.

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200-901 Software Development and Design Practice Question

Why each option matters

Option-by-option breakdown

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