200-901 Software Development and Design Practice Question
A Python script uses a list comprehension: [x**2 for x in range(20) if x % 2 == 0]. Which of the following is equivalent?
⚠ Common exam trap
Cisco often tests the distinction between list comprehensions with and without a filtering condition, and the trap here is that candidates may overlook the `if x % 2 == 0` filter and choose Option C, which omits the condition entirely.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
result = [] for x in range(20): if x % 2 == 0: result.append(x**2)
It directly translates the list comprehension into an equivalent for-loop with a conditional append. The comprehension `[x**2 for x in range(20) if x % 2 == 0]` iterates over numbers 0–19, filters for even numbers (x % 2 == 0), squares each, and collects the results in a list. Option A's explicit loop and conditional produce the exact same sequence of appended values.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✓
result = [] for x in range(20): if x % 2 == 0: result.append(x**2)
Why this is correct
This loop explicitly does the same filtering and squaring.
- ✗
result = map(lambda x: x**2, filter(lambda x: x % 2 == 0, range(20)))
Why it's wrong here
While functional, it returns a map object, not a list; but list(map(...)) would be equivalent. However, the question asks for equivalent code, and this answer is not a complete list conversion. The loop is the most direct equivalent.
- ✗
result = [] for x in range(20): result.append(x**2)
Why it's wrong here
This appends squares of all numbers, not just even ones.
- ✗
result = [x**2 for x in range(20) if x % 2 != 0]
Why it's wrong here
This selects odd numbers, the opposite condition.
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