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200-901 Network Fundamentals Practice Question

A network administrator needs to assign IP addresses to devices on a subnet with a /25 prefix. How many usable host addresses are available?

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

126

A /25 subnet has 7 bits for hosts (32-25=7), giving 2^7 = 128 total addresses, minus 2 (network and broadcast) = 126 usable hosts.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • 254

    Why it's wrong here

    254 is for a /24 subnet.

  • 126

    Why this is correct

    2^(32-25) - 2 = 128 - 2 = 126.

  • 64

    Why it's wrong here

    64 is for a /26 subnet.

  • 128

    Why it's wrong here

    128 is the total number of addresses including network and broadcast.

Visual reference

192.168.1.0 /24 256 addresses (254 usable) 192.168.1.0 /25 Subnet A 128 addr (126 usable) 192.168.1.128 /25 Subnet B 128 addr (126 usable) Borrowing 1 bit from host portion creates 2 subnets (/25)

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JA

Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

This 200-901 practice question is part of Courseiva's free Cisco certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 200-901 exam.