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200-901 Practice Question: A network administrator needs to assign IP…

A network administrator needs to assign IP addresses to 50 hosts in a subnet. Which subnet mask provides the minimum required number of usable addresses while minimizing waste?

⚠ Common exam trap

Cisco often tests the distinction between 'total addresses' and 'usable addresses' — candidates mistakenly count the total 64 addresses as usable, forgetting to subtract the network and broadcast addresses, or they choose a mask that provides exactly 50 total addresses (which is impossible since host bits must be a power of 2).

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

255.255.255.192 (/26)

A /26 subnet mask (255.255.255.192) provides 64 total addresses per subnet, of which 62 are usable (2^6 - 2 = 62). This is the smallest power-of-two block that can accommodate 50 hosts, minimizing waste while meeting the requirement.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • ✓

    255.255.255.192 (/26)

    Why this is correct

    A /26 mask yields 64 addresses, leaving 62 usable after reserving network and broadcast, which covers 50 hosts with only 12 wasted. Smaller masks such as /27 provide just 30 usable addresses, insufficient here, so /26 is the tightest fit satisfying the minimum-address constraint.

  • ✗

    255.255.255.224 (/27)

    Why it's wrong here

    A /27 mask yields 30 usable addresses, which cannot accommodate 50 hosts, so the requirement fails outright. It is tempting because /27 subnets suit small segments of up to 30 devices, such as point-to-point links or tiny departmental VLANs, where conserving address space matters more than host capacity.

  • ✗

    255.255.255.240 (/28)

    Why it's wrong here

    A /28 yields 16 addresses, only 14 usable after network and broadcast, so it cannot accommodate 50 hosts. It is tempting because /28 subnets suit small segments such as point-to-point links or tiny VLANs, where 14 usable addresses suffice. Here the requirement is 50 hosts, which needs at least a /26.

  • ✗

    255.255.255.128 (/25)

    Why it's wrong here

    A /25 mask yields 126 usable addresses, far exceeding the 50 hosts required, so it wastes 76 addresses. It is tempting because /25 is the natural choice when a subnet must be split into two equal halves, such as separating two departments of roughly 60 devices each.

Visual reference

192.168.1.0 /24 256 addresses (254 usable) 192.168.1.0 /25 Subnet A 128 addr (126 usable) 192.168.1.128 /25 Subnet B 128 addr (126 usable) Borrowing 1 bit from host portion creates 2 subnets (/25)

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Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

This 200-901 practice question is part of Courseiva's free Cisco certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 200-901 exam.