- A
ip.src == 10.0.0.1 and tcp.dstport == 80
This filter correctly specifies the source IP and destination TCP port.
- B
ip.src eq 10.0.0.1 and tcp.dstport eq 80
Why wrong: 'eq' is not valid Wireshark syntax; use '=='.
- C
src 10.0.0.1 and dst port 80
Why wrong: 'src' and 'dst port' are not valid display filter fields.
- D
host 10.0.0.1 && port 80
Why wrong: This is a capture filter syntax, not a display filter.
Question 748 of 1,000
200-201 Security Monitoring Practice Question
This 200-201 practice question tests your understanding of security monitoring. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
In Wireshark, a security analyst wants to display only packets with source IP 10.0.0.1 and destination port 80. Which display filter should be used?
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
ip.src == 10.0.0.1 and tcp.dstport == 80
Option A is correct because Wireshark display filters use specific syntax: `ip.src` for source IP and `tcp.dstport` for destination TCP port. The `==` operator is the standard equality operator in Wireshark display filters, and the filter `ip.src == 10.0.0.1 and tcp.dstport == 80` correctly matches packets where the source IP is exactly 10.0.0.1 and the destination TCP port is exactly 80.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✓
ip.src == 10.0.0.1 and tcp.dstport == 80
Why this is correct
This filter correctly specifies the source IP and destination TCP port.
Related concept
Read the scenario before looking for a memorised answer.
- ✗
ip.src eq 10.0.0.1 and tcp.dstport eq 80
Why it's wrong here
'eq' is not valid Wireshark syntax; use '=='.
- ✗
src 10.0.0.1 and dst port 80
Why it's wrong here
'src' and 'dst port' are not valid display filter fields.
- ✗
host 10.0.0.1 && port 80
Why it's wrong here
This is a capture filter syntax, not a display filter.
Common exam traps
Common exam trap: answer the scenario, not the keyword
Cisco often tests the distinction between capture filter syntax (used with `tcpdump` or Wireshark's capture options) and display filter syntax (used in Wireshark's filter bar), so candidates who confuse `eq` or `host`/`port` keywords with proper display filter fields will select a wrong answer.
Detailed technical explanation
How to think about this question
Wireshark display filters use a field-based syntax tied to the protocol dissectors, allowing precise matching of packet headers. The `ip.src` field refers to the source IP address in the IPv4 header, while `tcp.dstport` refers to the destination port in the TCP header. A common subtlety is that `tcp.dstport` only matches TCP traffic; if the analyst intended to also capture UDP port 80, they would need `udp.dstport` or a combined filter like `tcp.dstport == 80 or udp.dstport == 80`.
KKey Concepts to Remember
- Read the scenario before looking for a memorised answer.
- Find the constraint that changes the correct option.
- Eliminate answers that are true in general but not in this case.
TExam Day Tips
- Watch for words such as best, first, most likely and least administrative effort.
- Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
How this comes up in practice
A practitioner preparing for the 200-201 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
Visual reference
What to study next
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FAQ
Questions learners often ask
What does this 200-201 question test?
Security Monitoring — This question tests Security Monitoring — Read the scenario before looking for a memorised answer..
What is the correct answer to this question?
The correct answer is: ip.src == 10.0.0.1 and tcp.dstport == 80 — Option A is correct because Wireshark display filters use specific syntax: `ip.src` for source IP and `tcp.dstport` for destination TCP port. The `==` operator is the standard equality operator in Wireshark display filters, and the filter `ip.src == 10.0.0.1 and tcp.dstport == 80` correctly matches packets where the source IP is exactly 10.0.0.1 and the destination TCP port is exactly 80.
What should I do if I get this 200-201 question wrong?
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
What is the key concept behind this question?
Read the scenario before looking for a memorised answer.
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Last reviewed: Jul 4, 2026
This 200-201 practice question is part of Courseiva's free Cisco certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 200-201 exam.
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