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200-201 Security Monitoring Practice Question

During a security investigation, an analyst examines a PCAP file in Wireshark. The analyst wants to see only traffic between two specific IP addresses (192.168.1.10 and 10.0.0.5). Which display filter should be applied?

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

ip.addr==192.168.1.10 && ip.addr==10.0.0.5

The correct display filter uses 'ip.addr' to match either direction. The syntax 'ip.addr==192.168.1.10 && ip.addr==10.0.0.5' shows packets where both addresses appear, which is correct for traffic between them.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • ✗

    tcp.port==80

    Why it's wrong here

    This filters by port 80, not by IP addresses.

  • ✗

    ip.src==192.168.1.10 and ip.dst==10.0.0.5

    Why it's wrong here

    This only shows one direction, not both.

  • ✓

    ip.addr==192.168.1.10 && ip.addr==10.0.0.5

    Why this is correct

    This filter includes packets where either IP is source or destination, covering both directions.

  • ✗

    ip.addr eq 192.168.1.10 or ip.addr eq 10.0.0.5

    Why it's wrong here

    This would show packets involving either IP, not necessarily between them.

Visual reference

Source Router + ACL permit 10.0.0.0/8 deny any Server 10.0.0.5 ✓ 192.168.1.1 ✗ dropped ACLs evaluate top-down; first match wins — implicit deny all at end

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JA

Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

This 200-201 practice question is part of Courseiva's free Cisco certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 200-201 exam.