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MLS-C01 Modeling Practice Question

A data scientist is building a model to predict insurance claim amounts. The target variable is right-skewed with many small claims and a few very large claims. The scientist wants to minimize the impact of outliers. Which loss function or transformation is MOST appropriate?

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

Apply a log transformation to the target variable

Applying a log transformation to the target variable reduces skewness and mitigates the impact of outliers by compressing the scale of large values. This makes the distribution more symmetric and suitable for models like linear regression. Option A (mean squared error) is sensitive to outliers. Option B (quantile loss) predicts the median, which is robust but not typical for mean prediction. Option C (Poisson loss) is designed for count data, not continuous skewed targets. Option D (log transformation) is the standard approach for right-skewed continuous targets.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • Use mean squared error loss without any transformation

    Why it's wrong here

    MSE is sensitive to outliers and will be dominated by large claims.

  • Use quantile loss to predict the median

    Why it's wrong here

    Quantile loss predicts a quantile, not the mean, and may not be appropriate for expected claim amount.

  • Use Poisson loss assuming the target follows a Poisson distribution

    Why it's wrong here

    Poisson loss is for non-negative count data, not continuous amounts.

  • Apply a log transformation to the target variable

    Why this is correct

    Log transformation reduces skewness and makes the distribution more symmetric, reducing outlier impact.

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