- A
Use 'coalesce(n)' with n based on target file size (e.g., 128 MB) before writing.
Coalesce reduces partitions without a full shuffle, minimizing files.
- B
Enable S3 multipart upload for the Glue job.
Why wrong: Multipart upload is for large files, not file count.
- C
Increase the 'spark.sql.shuffle.partitions' to 500.
Why wrong: Increases parallelism, leading to more files.
- D
Reduce the 'spark.sql.shuffle.partitions' to 50.
Why wrong: Reduces parallelism, may cause OOM, but still produces many small files.
DEA-C01 Data Ingestion and Transformation Practice Question
This DEA-C01 practice question tests your understanding of data ingestion and transformation. Match the stated requirement to the specific cloud service, access model, or configuration option — many options are valid in isolation but not for this scenario. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
A company runs an AWS Glue ETL job that reads data from Amazon S3, transforms it, and writes back to S3 in a different partition structure. The job uses the 'spark.sql.shuffle.partitions' option set to 200. After the job completes, the output has many small files. The data engineer wants to minimize the number of output files while maintaining job performance. Which action should the engineer take?
Clue words in this question
Noticing these words before you look at the options changes how you read each choice.
Clue:
"minimum / minimize"Why it matters: Asks for the least resource use — fewest addresses, smallest subnet, lowest overhead. Eliminate over-provisioned options even if they would technically work.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
Use 'coalesce(n)' with n based on target file size (e.g., 128 MB) before writing.
Option A is correct because 'coalesce(n)' reduces the number of partitions without triggering a full shuffle, allowing you to control the number of output files based on a target file size (e.g., 128 MB). This minimizes small files while preserving job performance, as coalesce is a narrow transformation that avoids the overhead of a shuffle. In contrast, 'repartition(n)' would cause a full shuffle, degrading performance.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✓
Use 'coalesce(n)' with n based on target file size (e.g., 128 MB) before writing.
Why this is correct
Coalesce reduces partitions without a full shuffle, minimizing files.
Clue confirmation
The clue word "minimum / minimize" in the question point toward this answer.
Related concept
Read the scenario before looking for a memorised answer.
- ✗
Enable S3 multipart upload for the Glue job.
Why it's wrong here
Multipart upload is for large files, not file count.
- ✗
Increase the 'spark.sql.shuffle.partitions' to 500.
Why it's wrong here
Increases parallelism, leading to more files.
- ✗
Reduce the 'spark.sql.shuffle.partitions' to 50.
Why it's wrong here
Reduces parallelism, may cause OOM, but still produces many small files.
Common exam traps
Common exam trap: answer the scenario, not the keyword
The trap here is that candidates often confuse 'coalesce' with 'repartition' or assume that adjusting 'spark.sql.shuffle.partitions' directly controls output file count, when in fact it only controls the number of partitions during shuffle operations, not the final write partition count.
Detailed technical explanation
How to think about this question
Under the hood, 'coalesce(n)' works by merging existing partitions without a full shuffle, using narrow dependencies that minimize data movement across executors. This is particularly effective when the number of output files is too high due to many small partitions, as it combines them into fewer, larger partitions. In real-world scenarios, targeting a file size of 128 MB (matching S3's optimal read chunk size) can significantly reduce S3 LIST and GET costs, and improve downstream processing performance.
KKey Concepts to Remember
- Read the scenario before looking for a memorised answer.
- Find the constraint that changes the correct option.
- Eliminate answers that are true in general but not in this case.
TExam Day Tips
- Watch for words such as best, first, most likely and least administrative effort.
- Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
How this comes up in practice
A media company stores terabytes of video archives that are accessed once a year for audit purposes. Moving these objects to a cold storage tier (Azure Archive, S3 Glacier, or Google Nearline) costs a fraction of hot storage. Questions like this test whether you understand storage tiers, access frequency tradeoffs, and retrieval latency requirements.
Quick reference
AWS S3 Storage Class Comparison
| Storage Class | Min Duration | Retrieval | Use Case |
|---|---|---|---|
| S3 Standard | None | Immediate | Frequently accessed data |
| S3 Standard-IA | 30 days | Immediate | Infrequent access, rapid retrieval |
| S3 One Zone-IA | 30 days | Immediate | Non-critical infrequent data |
| S3 Intelligent-Tiering | None | Immediate–hours | Unknown or changing access patterns |
| S3 Glacier Instant | 90 days | Milliseconds | Archive with instant retrieval |
| S3 Glacier Flexible | 90 days | Minutes–hours | Archive, flexible retrieval |
| S3 Glacier Deep Archive | 180 days | Hours | Long-term compliance archive |
What to study next
Got this wrong? Here's your next step.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
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FAQ
Questions learners often ask
What does this DEA-C01 question test?
Data Ingestion and Transformation — This question tests Data Ingestion and Transformation — Read the scenario before looking for a memorised answer..
What is the correct answer to this question?
The correct answer is: Use 'coalesce(n)' with n based on target file size (e.g., 128 MB) before writing. — Option A is correct because 'coalesce(n)' reduces the number of partitions without triggering a full shuffle, allowing you to control the number of output files based on a target file size (e.g., 128 MB). This minimizes small files while preserving job performance, as coalesce is a narrow transformation that avoids the overhead of a shuffle. In contrast, 'repartition(n)' would cause a full shuffle, degrading performance.
What should I do if I get this DEA-C01 question wrong?
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Are there clue words in this question I should notice?
Yes — watch for: "minimum / minimize". Asks for the least resource use — fewest addresses, smallest subnet, lowest overhead. Eliminate over-provisioned options even if they would technically work.
What is the key concept behind this question?
Read the scenario before looking for a memorised answer.
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Last reviewed: Jul 4, 2026
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